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Nata [24]
2 years ago
8

The equation y=x^2-12x+45 models the number of books y sold in a bookstore x days after an award-winning author appeared at an a

utograph-signing reception.
How many books were sold at the autograph session?

What is the minimum nunber of books sold?

What day did that occur?

How many books were sold on day fifteen?​
Mathematics
2 answers:
choli [55]2 years ago
7 0

Answer:

3.2

Step-by-step explanation:

xz_007 [3.2K]2 years ago
3 0

Answer:

Answer: The first day the author reaches 100 days is on day 16.

To solve this problem, you could use a graphing calculator to graph the given equation. Then, determine when this line crosses 100. It crosses when x = 15.539. Therefore, we would have to round up to 16 so it is at least 100.

You could use the quadratic equation to solve: 100 = x^2 -12x + 45

Either you will get 16. If you use the quadratic formula, make sure to only use the positive answer.

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Sam wants to find the best buy on cans of tuna. He reads these four ads in the newspaper.$12.53 for seven cans$5.97 for three ca
grandymaker [24]
In each case divide the price by the number of cans.
The best buy is the lowest price.
$12.53/7 = $1.79
$5.97/3 = $1.99
$7.95/5 = $1.59
$8.34/6 = $1.39

The fourth ad, $8.34 for 6 cans results in the lowest price per can, $1.39.
The fourth ad is the best buy.
8 0
3 years ago
What is the difference in the range of temperature between the two years
REY [17]
Send a picture so i can answer it
3 0
3 years ago
Math help questions <br>​
Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of \$800 \times 1.07^t.

We want the find the number of years n such that

\$856 \times 1.07^n = \$1400

Solve for n :

856 \times 1.07 ^n = 1400

1.07^n = \dfrac74

\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)

n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)

n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}

4 0
1 year ago
Read 2 more answers
Find the area of the parallelogram. <br> Help pls and thank you.
aliina [53]

Answer:

24

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I need to get to 100 percent please help me this is due tomorrow
Amiraneli [1.4K]
Maybe 120-130
As it’s more than 90 but slightly less than 135
4 0
2 years ago
Read 2 more answers
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