All categories

2 years ago

Could someone please help

Mathematics

2 answers:

Leno4ka [110]2 years ago

8 0

The answer is 5 and six because you add

lubasha [3.4K]2 years ago

7 0

Answer:

the answer is 6 ok

hope it helped

You might be interested in

Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on

Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

If he is given with two kings.
If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by = $\frac{^{3}C_2 }{^{47}C_2}$ {∵ one king is already there}

= $\frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}$ {∵ $^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{3}{1081}$ = 0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by = $\frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}$

= $\frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}$

= $\frac{6}{1081}$ = 0.0055

Now, probability that he ends up with a full house = $\frac{3}{1081} + \frac{6}{1081}$

= $\frac{9}{1081}$ = <u>0.0083</u>.

3 0

3 years ago

Read 2 more answers

Please help, I will mark!!

Alik [6]

Answer:

$d=28.28$

Step-by-step explanation:

To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.

<em>The Pythagorean theorem</em> states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:

$a^{2} +b^{2} =c^{2}$ a is the height, b is the base, and c is

the hypotenuse.

To obtain the value of the hypotenuse

$c= \sqrt{a^{2} +b^{2} }$

To find the value of the lenght of the diagonal d across the square, we have:

$d=\sqrt{a^{2} +b^{2} }$ Where a = b = 20

Substituting the values

$d=\sqrt{(20)^{2} +(20)^{2} }\\d=\sqrt{400+400} =\sqrt{800} \\d=28.284$

Round the answer to 2 decimal places

$d=28.28$

6 0

3 years ago

Phoebe wants to get atleast a grade of 90 in the math class. Her grade will be the average of two tests. She scored a 94 on the

marin [14]

First things first, you will have 94 + x. Place those on top of a fraction bar and on the bottom put the two numbers over 2. So you have 94 + x over 2. Then, write the symbol ‘greater than or equal to’ and on the other side place your 90. So, 90 + x over 2 is greater than or equal to 90. This is a difficult thing to write out and explain so I hope this makes sense. :)

7 0

3 years ago

Read 2 more answers

Write an equation of the line below.

statuscvo [17]

Answer:

y = -4x - 4

Step-by-step explanation:

Rise/Run

-8/2 = -4

Y-intercept:

-4

8 0

3 years ago

Five less than the qouicent of number of a number and 3 is -7

Nuetrik [128]

Sorry. Had to redo this with the correct answer.

Here it is...

Solve for x by simplifying both sides of the equation, then isolating the variable.

Exact Form:

x = - 2/5 (fraction)

Decimal Form:

x = - 0.4 (decimal)

7 0

3 years ago