A large game cube with a four-inch side length is wrapped with shrink wrap. How many square inches of shrink wrap will be used t
1 answer:
Answer:
864 square inches
Step-by-step explanation:
To solve this problem, first we need to know the area of each side of the cube(since the shrink wrap will cover these sides) :
The area of each side is A= where L is the length of the side. In this case, L= 4 inches.
Thus, the area of each side is square inches.
However, the cube has 6 sides so we have to multiply the area of each side by 6, this gives us square inches. Thus, we need 96 square inches of shrink wrap for each cube.
Now, we have nine cubes, so we have to multiply those 96 square inches by 9, .
Thus, we need 864 square inches of shrink wrap to wrap 9 cubes.
You might be interested in
Answer:
Step-by-step explanation:
Hello!
a.
Using the data sets you have to analyze them as if they are two independent samples.
The hypotheses are:
H₀: μ₁=μ₂
H₁: μ₁≠μ₂
α: 0.05
Assuming that both data sets are from a normal distribution and both population variances, although unknown, are equal, the statistic to use is:
Sa= 2.12
The p-value for the two-tailed test is:
P(≤-0.875) + P(
≥0.875)= P(
≤-0.875) + (1 - P(
≤0.875))= 0.1965 + ( 1 - 0.8035)= 0.393
Since there is no significant level I determined it at 5%, comparing it to the p-value, the hypothesis test is not significant. Meaning that the difference between the population means of both groups is equal to zero.
b.
Considering the given data as a paired sample, you have to determine the variable difference to conduct the test:
Xd: the difference between X₁ and X₂
Before the sample mean and sample standard deviation you have to calculate the difference between the observations of group 1 and group 2. (2nd attachment)
Mean X[bar]d= -0.83
Standard deviation Sd= 1.28
The hypotheses for the paired sample test are:
H₀: μd=0
H₁: μd≠0
α: 0.05
The p-value for the two-tailed test is:
P(≤-2.05) + P(
≥2.05)= P(
≤-2.05) + (1 - P(
≤2.05))= 0.0353 + (1 - 0.9647)= 0.0706
Comparing the p-value with the significance level, the hypothesis test is not significant. Meaning that the population mean of the difference between group 1 and group 2 is equal to cero. There is no difference between the two groups.
c.
The value of the statistic in "a" is greater than the value of the statistic obtained in "b". Since there are two samples used an "a" the degrees of freedom of the test are the double as the ones used in "b". The p-value obtained in "b" is around half of the p-value of "a".
The main difference is that in "a" you compared two different samples but in "b" you compared two dependent samples when analyzing paired data the "effect of the individual" is removed from the equation.
I hope this helps!
