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Artyom0805 [142]
3 years ago
12

Which statement is true? A. A biconditional is only true if both statements are true. B. A biconditional is only true if both st

atements have the same truth value. C. A biconditional is only true if the hypothesis is true. D. A biconditional is only true if the hypothesis is false.
Mathematics
2 answers:
Charra [1.4K]3 years ago
6 0
The answer is B. I hope this helps.
Citrus2011 [14]3 years ago
6 0
<h2>Answer:</h2>

Option: B is the correct answer.

   B. A biconditional is only true if both statements have the same truth value.

<h2>Step-by-step explanation:</h2>

<u>Biconditional statement--</u>

A statement is said to be a biconditional statement if it is given in the form:

           p if and only if q

where p is the hypotheses and q is the conclusion of the statement.

Also, the statement is true only if both the statements have the same truth values otherwise it is  false.

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The population of Virginia is 30% less than the population of Georgia. If
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7,150,000

The population of Georgia is 10,500,000.

The population of Virginia is 30% less than that.

So the population of Virginia is 10,500,000 - 30% which equals 7,150,000

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3 years ago
The formula for computing the feet is .
nexus9112 [7]

Answer:

When you have to get these measurements completely then you apply some multiplication as follows: Calculate cubic feet for different units (formula) From feet: length (ft) × width (ft) × height (ft) = cubic feet From inches: length (in) × width (in) × height (in) ÷ 1728 = cubic feet

Step-by-step explanation:

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A square root is categorized as what kind of number?<br><br> Choices:<br> Irrational <br> Rational
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<span>Rational i believe is the answer i ain't for sure though</span>
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3 years ago
Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.
Andre45 [30]

Answer:

Option d)  5 to the power of negative 5 over 6 is correct.

\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}

Above equation can be written as 5 to the power of negative 5 over 6.

ie, 5^\frac{\bf -5}{\bf 6}

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}

\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}

Above equation can be written as 5 to the power of negative 5 over 6.

7 0
4 years ago
Solve the problem below, simplify, add steps<br> 1/3 √21 minus 2/3 √3 * √7
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</span></span>
4 0
3 years ago
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