Assuming that Anita needs hollow right circular cones, we are solving for its lateral surface area, which is given by the formula πr√(h²+r²), where r is the radius and h is the height.
r = 6 ft / 2 = 3 ft
Solving for the lateral surface area of one cone:
LSA = (3.14) (3) [√(12²+3²)] = 116.52 sq ft.
Since she needs 10 cones:
10 * 116.52 sq. ft = 1,165.2 sq ft.
She will need 1,165.2 sq ft of material.
Step-by-step explanation:
https://youtu.be/dQw4w9WgXcQ
Problem 1
<h3>Answer: 7/10</h3>
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Explanation:
The formula we'll use is
P(A or B) = P(A) + P(B)
which only works if A and B are mutually exclusive events.
P(A or B) = P(A) + P(B)
P(A or B) = 7/20 + 7/20
P(A or B) = (7+7)/20
P(A or B) = 14/20
P(A or B) = (7*2)/(10*2)
P(A or B) = 7/10
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Problem 2
<h3>Answer: 3/4</h3>
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Explanation:
We'll use the same formula as the previous problem.
P(A or B) = P(A) + P(B)
P(A or B) = 3/10 + 9/20
P(A or B) = 6/20 + 9/20
P(A or B) = (6+9)/20
P(A or B) = 15/20
P(A or B) = (3*5)/(4*5)
P(A or B) = 3/4
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Problem 3
<h3>Answer: 3/5</h3>
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Explanation:
We'll use the same formula as the previous problem.
P(A or B) = P(A) + P(B)
P(A or B) = 7/20 + 1/4
P(A or B) = 7/20 + 5/20
P(A or B) = (7+5)/20
P(A or B) = 12/20
P(A or B) = (4*3)/(4*5)
P(A or B) = 3/5
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Problem 4
<h3>Answer: 0</h3>
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Explanation:
This time we're asked to find P(A and B), but since the two events are mutually exclusive, this means the probability of both occurring is 0.
Mutually exclusive events cannot happen simultaneously.
An example would be flipping heads and tails at the same time on the same coin.
The info about P(A) and P(B) is not relevant.
Answer:140, 125, 110
Step-by-step explanation:
Each is subtracted by 15
210-15 = 195
195-15 = 180
180-15 = 165
165-15 = 140
140-15 = 125
125- 15 = 110
12/6 you have to put it on top and bottom then subtract
