Let the number of dimes = xLet the number of quarters = y You know that each dime is worth $0.10You know that each quarter is worth $0.25 Using the variables above, we can write two equations that represents the total number of coins and total amount. x + y = 47 eq10.10x + 0.25y = 8 eq2 You can use the substitution/elimination method to solve for x and y.<span>3/6/2017 </span>| Michael J.<span>
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Answer:
314 m²
Step-by-step explanation:
the formula for the surface area of a sphere (As) is
As = 4×pi×r²
the radius r (half of the diameter) is clearly indicated as 5m.
so, As = 4×3.14×5² = 4×3.14×25
I don't even need a calculator for this, as 4×25 = 100
so, As = 100×3.14 = 314
(you know, when multiplying by 10, the decimal point moves right one position. multiply by 100 it moves 2 positions, and so on).
You want to draw 2 kings from a 52 card deck. And you do it with replacement.
There are 4 kings in a standard deck. The probability of getting one of them is
4/52 on the first draw.
For the second draw the probability is the same.
4/52
The probability for both happening is
(4/52)*(4/52) = (1/13)*(1/13) = 1/169 = 0.001597
The length of the third smallest table is 1.6 because 7.8 is more than 3.5 and 3.5 is more than 1.6,
Answer:
80/81
Step-by-step explanation:
If a head is twice as likely to occur as a tail, then the probability of getting heads is 2/3 and the probability of getting tails is 1/3.
The probability of getting at least 1 head involves 4 scenarios:
1) 1 Head and 3 Tails
2) 2 Heads and 2 Tails
3) 3 Heads and 1 Tail
4) 4 Heads
Instead of calculate all these scenarios, you could calculate the opposite scenario: 4 Tails. The sum of all possible scenarios is 1, so:
P(at least one head) + P(no heads) = 1
Then, P(at least one head) = 1 - P(no heads)
The probability of 4 tails is:
P(no heads) = P(TTTT) = (1/3)(1/3)(1/3)(1/3)=1/81
Then, P(at least one head) = 1 - 1/81=80/81
