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Ghella [55]
3 years ago
12

Find the volume of the prism height 8cm length 12cm width 6cm

Mathematics
2 answers:
Arisa [49]3 years ago
8 0

Answer:

576cm

Step-by-step explanation:

12 times 8 = 96 and 96 x 6 is 576

kari74 [83]3 years ago
5 0

Answer:

length l = 12 cm

width w = 6 cm

height h = 8 cm

diagonal d = 15.620499351813 cm

surface area S = 432 cm²

volume V = 576 cm³

Step-by-step explanation:

Volume of Rectangular Prism:

V = lwh

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Rename 5/6 and 5/8 using the least common denominator.
Marina CMI [18]

Answer:

5/6 = 20/24

5/8 = 15/24

Step-by-step explanation:

These are the answers because:

1) First, the least common denominator is 24 because 8 x 3 is 24 and 6 x 4 is 24

2) Next, multiply the numerators with the same number you multiplied with the denominator

5 x 3 = 15

5 x 4 = 20

3) Therefore, the answers are:

5/6 = 20/24

5/8 = 15/24

Hope this helps!

6 0
3 years ago
Suppose r(140°, P)(A) = B and (RPD←→∘RPC←→)(A) = B, what is m∠CPD?
NISA [10]

An angle bisector divides an angle into two equal halves.

The measure of angle \angle CPD is 70 degrees

The complete question is an illustrates the concept of angle bisector;

Where:

\angle RPD = 140^o, and line PC bisects \angle RPD

Because line PC bisects \angle RPD, then it means that the measure of RPD is twice the measure of CPD:

So, we have:

\angle RDP = 2 \times \angle CPD

Substitute \angle RPD = 140^o

140^o = 2 \times \angle CPD

Divide both sides by 2

70^o = \angle CPD

Apply symmetric property of equality:

\angle CPD = 70^o

Hence, the measure of angle \angle CPD is 70 degrees

Read more about angle bisectors at:

brainly.com/question/12896755

5 0
3 years ago
BREE<br> In which diagram do angles 1 and 2 form a linear pair?<br> 1<br> 2
Tresset [83]
Where’s the diagrams???
6 0
3 years ago
What base-ten number is 14 tens and 4 ones?¿
MrMuchimi

Answer:144


Step-by-step explanation:


7 0
4 years ago
(4x5 + 9x3 - 12x8) + (8x3 - 7x + 2x5)
SSSSS [86.1K]

Answer:

-10x5 + 8x4 - 7x3 - 20x2 - x + 18

Step-by-step explanation:

8 0
3 years ago
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