Answer:
Length of spaceship in movie = 528
Step-by-step explanation:
Given that:
Drawing ratio of spaceship = 1 : 24
It means that 1 inch on drawing equals 24 inches in movie
Drawing of spaceship = 22 inches
Length of spaceship in movie = x
As the relationship is proportional,
1 : 24 :: 22 : x
Product of mean = Product of extreme
24*22 = x
x = 528
Hence,
Length of spaceship in movie = 528
Answer:
A
Step-by-step explanation:
Alright, this may come out weird on computer, but here we go.
First, you want to change this into a multiplication problem, with Keep change flip. So now it's (c^2-c-20/c^2-6c+5) * (3c-3/c^2-16). You then want to simplify some number down.
You can simplify the first part using the X game (not sure if you know this), but you put the c value at the top, and the B value at the bottom, and the two sides blank. These two values must add to equal the C value, but multiply to equal the B value, so you get -5 and 4 for the numerator of the top. Following this formula, and using difference of perfect squares, you'll end up with the following.
(c-5)(c+4)/(c-5)(c-1) * 3(c-1)/(c+4)(c-4)
You then need to cancel out your different groups, so you'll cancel out (c-5), (c+4), (c-1).
After all that, you'll end up with 3/c-4, so the answer is A.
Answer:
Step-by-step explanation:
Ive already explained this somebody else asked if you find it you will have the answer
The matrix R represents the reflection matrix for the provided vertices, and graph A represents the pre-image and the image on the same coordinate grid.
<h3>What is the matrix?</h3>
It is defined as the group of numerical data, functions, and complex numbers in a specific way such that the representation array looks like a square, rectangle shape.
We have vertices shown in the picture.
Form a matrix using the vertices:
![= \left[\begin{array}{ccc}-3&5&6\\7&3&-5\\\end{array}\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%266%5C%5C7%263%26-5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To reflect over the x-axis, multiply by the reflection matrix:
![= \left[\begin{array}{ccc}1&0\\0&-1\\\end{array}\right]\left[\begin{array}{ccc}-3&5&6\\7&3&-5\\\end{array}\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%266%5C%5C7%263%26-5%5C%5C%5Cend%7Barray%7D%5Cright%5D)
![\rm R= \left[\begin{array}{ccc}-3&5&6\\-7&-3&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Crm%20R%3D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%266%5C%5C-7%26-3%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The above matrix represent the reflection matrix.
Thus, the matrices R represents the reflection matrix for the provided vertices, and graph A represents the pre-image and the image on the same coordinate grid.
Learn more about the matrix here:
brainly.com/question/9967572
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