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dmitriy555 [2]
3 years ago
11

↓↓↓↓↓↓↓↓↓↓↓↓↓ Help with all No words EXTRA POINTS!!!!

Mathematics
2 answers:
ivann1987 [24]3 years ago
6 0
<span><span><span>xy</span>−5</span>=k</span>  Flip the equation.<span>  k=<span><span>xy</span>−5</span></span>
Answer is <span>k=<span><span>xy</span>−<span>5
I hope this helps

</span></span></span>
sveta [45]3 years ago
6 0
Xy - 5 = k (move the known term to the right with changed sign)

xy = k + 5

Now we have x multiplied for y...to delete the y, divide both terms for y.

xy/y = (k+5)/y

x = (k+5)/y

3y + 5x = 7

Move 3y to the right with changed sign (this to make x the variable for which we solve the equation)

5x = 7 - 3y

Divide every term for 5

5x/5 = 7/5 - 3y/5

x = 7/5 - 3y/5

m/n = p-6

Multiply both terms for n, since we should delete the fraction m/n

m = pn-6n

Factor...

m = n(p-6)

to find n, move m to the right with changed sign.

Divide both for p-6

m/p-6 = n

n = m/p-6

F = 9c/5 + 32

9c/5 + 32 = F

Move 9c/5 to the left (don't change sign) to make it the default variable. And move all the rest to the right but changing sign.

9c/5 = f - 32

To delete the fraction, multiply every term for 5

9c = 5(f) + 32(5)

9c = 5f - 160

Divide both for 9

c = 5f/9 - 160/9
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4 years ago
Which of the following relation graphs represents a function?<br> A.
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Answer:

The third one (parabola)

Step-by-step explanation:

Do a vertical line test.

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3 years ago
An architect charges 300 dollars for each project and an additional 32 dollars per hour during the project. In the most recent p
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8 0
3 years ago
(7) - (0)<br><br> (-2) - (7) <br><br> = <br><br> (Divide I’m pretty sure )
Alex777 [14]
Make a negative and positive number line and go from there
6 0
4 years ago
Given the vertices of ∆ABC are A (2,5), B (4,6) and C (3,1), find the vertices following each of the transformations FROM THE OR
djyliett [7]
The answer

a) the main rule for transformations <span>Rx-axis is as following
 original (x, y) --------------- the final coordinates become  (x, -y)

so the answer is  </span><span>A' (2, -5), B' (4,-6) and C' (3,-1)

b) just put the figure of y= 3, and check the value after projection

it is </span> A' (2, 1), B' (4,0) and C' (3,4)

c) <span>T<-2,5>, the main rule is as following

T(a, b) ----- applying on (x, y) is  (a+x, b+y) for the transformed points

in our case, </span><span>A' (0,10), B' (2,11) and C' (1,6)

d) the same method as above for </span><span>d. T<3,-6>, we found
</span><span>A '(5,-1), B '(7,0) and C ' (6,-5)


</span>
3 0
3 years ago
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