The equation of the line that is parallel to the given line and has an x-intercept of 3 is y = 2/3x - 2
<h3>What is the equation of the line that is parallel to the given line and has an x-intercept of 3?</h3>
The given parameters are
Point =(0, -1) and (3, 1)
Calculate the slope using
m = (y₂ - y₁)/(x₂ - x₁)
Where m represents the slope
So, we have:
m = (1 -- 1)/(3 -0)
Evaluate
m = 2/3
Parallel lines have equal slopes
So, the slope of the other line is
m = 2/3
Linear equations are represented as:
y = mx + c
Where m represents the slope and c represents the y-intercept
So, we have
y = 2/3x + c
An x-intercept of 3 means
0 = 2/3 * 3 + c
So, we have
c = -2
Substitute c = -2 in y = 2/3x + c
y = 2/3x - 2
Hence, the equation of the line that is parallel to the given line and has an x-intercept of 3 is y = 2/3x - 2
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Answer:
The lateral surface area of the triangular prism is 379.5sq units
Step-by-step explanation:
The side lengths of the base of the triangular prism are 5 meters, 8 meters, and 10 meters.
It is given that the height of the prism is 16.5 meters.
To determine the lateral surface area of the prism, let us use the formula
where a, b,c are the side lengths of the base of the triangular prism and h is the height of the prism.
Here and
Substituting these values in the formula, we have,
Simplifying, we get,
Multiplying, we get,
Thus, the lateral surface area of the triangular prism is
Answer:
|-49| < |-52|
Step-by-step explanation:
|-49| = 49
|-52| = 52
49 < 52
--> |-49| < |-52|
Answer:
2 Committees
Step-by-step explanation:
2 Committees and 3/4 of a committee
There are only 11 teachers so that means only 2 committees can be filled with 4 teachers if that is the max amount per committee.
There are more than enough students so no need to worry on them.
11 divided by 4 = 2.75
