Problem 17
Focus on one of the triangles. It has legs of 8 and 15. Use the pythagorean theorem to find the hypotenuse is 17.
Basically you're solving for c in a^2+b^2 = c^2. Use a = 8 and b = 15.
The diameter is 17 and the circumference is
C = pi*d = pi*17 = 17pi
<h3>Answer:
17pi</h3>
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Problem 18
This figure has four faces, so this is a tetrahedron. The "tetra" is greek that translates to "four".
Another possible name for this figure is triangular pyramid because we have a pyramid with a triangular base.
<h3>Answer: Triangular pyramid or tetrahedron</h3>
What do you neeeeeed help onnn i got youuuuu just tell meeeeeee
Y= 2x+6
You just have to go back wards from what you have. You already know the slope is 2 and slope is the change is y over the change in x. 2=2/1
So every time you take away 1 from x, you’re going to take away 2 from y.
(2,10) will become (1,8) which will be come (0,6).
You know have your y intercept (6)
So the equation for the line is y=2x+6
Answer: Your answer is -13.37500. Hope this helps!
Step-by-step explanation:
Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
