· Perpendicular lines have slopes that are opposite reciprocals of each other
· Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept
If the slope of the first line is 3, the slope of the second line is -1/3. Since the lines intersect at the origin, neither of them have a y-intercept.
Answer:
C) y = -1/3x
A graph can increase or decrease at an interval or several intervals
- The interval with the longest curve or line represents the greatest change.
- The intervals with the greatest rate of change are ab and de
- The intervals with the least rate of change are bc and cd
- The intervals with the equal rates of change are ab and de
<u>Part A: How to determine the longest interval</u>
The longest interval will have a great change in the y-values, and a small change in the x-values.
An instance of such interval is interval ab
<u>Part B: Intervals with the greatest rate</u>
Intervals ab and de have equal rates, and they cover the same vertical and horizontal distances, as described in (a) above.
Hence, intervals ab and de have the greatest rate of change
<u>Part C: Intervals with the least rate</u>
Intervals bc and cd have equal rates, and they cover the same vertical and horizontal distances,
Hence, intervals ab and de have the least rate of change
<u>Part D: Intervals with the equal rate</u>
As said in (b) and (c),
- Intervals ab and de have equal rates
- Intervals bc and cd have equal rates
Read more about intervals and rates at:
brainly.com/question/23483858
Answer:
10. Statement: Point P lies on line C'D'. Reason: The coordinates of P satisfy the equation of line C'D'.
Step-by-step explanation:
The equation for line C'D' in statement 8 appears to be in error. It should be ...
The coordinates of point P given in statement 9 are in error (they cannot be negative). They should be ...
P = (2/3(r+t), 2/3s) . . . . . without the minus signs
This point will satisfy the equation of line C'D'. Here is the algebra. (Notice we have multiplied each term on the right of the above equation by (-1/-1).
So, step 10 should say, in effect, P lies on C'D'.
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<em>Comment on the proof</em>
IMO it is unfortunate that this proof has so many mistakes. Properly done, it is a nice demonstration that the medians are concurrent. It also demonstrates that the location of the centroid is 1/3 of the distance along the median toward the vertex.
The 1 and 1 represent the 2 friends.
