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3 years ago

5

What is the equation of the line with an x-intercept of -1 and a y-intercept of 2?

1 answer:

iragen [17]3 years ago

4 0

Answer:

y = 2x + 2

Step-by-step explanation:

The general form

is;

y = mx + b

where m is the slope and b is the y-intercept

so we have;

y = mx + 2

To get m, substitute the point (-1,0)

So we have

0 = -m + 2

m = 2

So the equation is;

y = 2x + 2

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Need to find the value of y

alexgriva [62]

Answer:

√55

Step-by-step explanation:

Notice that the small triangle in the bottom corner shares an angle with the overall triangle. Also, they are both right triangles. Therefore, they are similar triangles.

Notice that the large triangle at the top shares an angle with the overall triangle and is also a right triangle. Therefore it is also similar to the overall triangle and the smaller triangle.

Writing a proportion between the small and large triangles:

y / 11 = 5 / y

y² = 55

y = √55

3 0

3 years ago

If ( 2 x 1) (0 x -1) = ( 15 ), then the value of x is

adoni [48]

Answer: x = -15/2

Step-by-step explanation:

This answer IS simplified

7 0

3 years ago

Explain how to find the slope of a given line given the intercepts of the line

scoundrel [369]

Answer:

y = m x + b equation of a line where m is the slope

m = (y2 - y1) / (x2 - x1)

Note: If the line passes thru the origin then m = y2 / x2 since

y1 = x1 = 0

6 0

3 years ago

Law of sines: StartFraction sine (uppercase A) Over a EndFraction = StartFraction sine (uppercase B) Over b EndFraction = StartF

Firdavs [7]

The length 2.3 and 7.8 units

We have given that ΔABC, c = 5. 4, a = 3. 3, and measure of angle A = 20 degrees.

<h3>What is the formula for low of cosine?</h3>

The Law of Cosines, which tells us

$a^{2}=b^{2} +c^{2} -2bccosA$

giving us a quadratic equation for b we can solve. But let's do it with the Law of Sines as asked.

$\frac{sinA}{a}=\frac{sinB}{b}=\frac{sinC}{c}$

We have c,a,A so the Law of Sines gives us sin C

$sinC=\frac{csina}{a} =\frac{5.4sin20}{3.3} =0.5597$

There are two possible triangle angles with this sine, supplementary angles, one acute, one obtuse

$C_{a}=arcsin(0.5597)=34.033^{0}$

$C_{0}=180-C_{a} =145.96^0$

Both of these make a valid triangle with A=20°. They give respective B's:

$B_{a}=180-A-C_{a} =125.96^0$

$B_{0}=180-C_{0} =14.033^0$

So we get two possibilities for b:

$b=\frac{asinB}{sinA} \\\\b_{a} =\frac{3.3sin125.96}{sin 20} \\\\b_{a}=7.8\\\\ b_0=2.3$

2.3 units and 7.8 units

Therefore we get the length 2.3 and 7.8 units

To learn more about the low of sine and cosine visit:

brainly.com/question/4372174

Answer: 2.3 units and 7.8 units

Let's check it with the Law of Cosines:

There's a shortcut for the quadratic formula when the middle term is 'even.'

Looks good.

4 0

2 years ago

If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5

Phoenix [80]

I hope this helps <span>24 = k * 6 </span><span>4 = k </span><span>y = kx </span><span>y = 4x </span><span>y = 4 * 5 </span><span>y = 20

</span>

6 0

4 years ago