Answer:
Overcoming Fear
Explanation:
Given that a movie theme stimulates a universal human ordeal and at the same time, Piper is a short animated movie that was released in 2016. The fundamental idea of the movie is about a baby sandpiper who has to survive and conquer his anxiety and phobia of the water.
Hence, in this situation, the theme that could come from Piper's feelings and action is OVERCOMING FEAR
Assuming you're running Windows, click the start button, and then search for "Device Manager" (or open CMD or PowerShell and type devmgmt.msc). Look at the list of devices. If Bluetooth is there, you have it; if it's not there, you don't.
Answer:
public void trimToSize() {
modCount++;
if (size < elementData.length) {
elementData = (size == 0)
? EMPTY_ELEMENTDATA
: Arrays.copyOf(elementData, size);
}
}
Now, the running time for copyOf() function is O(N) where N is the size/capacity of the ArrayList. Hence, the time complexity of trimToSize() function is O(N).
Hence, the running time of building an N-item ArrayList is O(N^2).
Please find the sample code below.
CODE
==================
import java.util.ArrayList;
public class Driver {
public static void main(String[] args) throws Exception{
int N = 100000;
ArrayList<Integer> arr = new ArrayList<>(N);
long startTime = System.currentTimeMillis();
for(int i=0; i<N; i++) {
arr.add(i);
arr.trimToSize();
}
long endTime = System.currentTimeMillis();
double time = (endTime - startTime)/1000;
System.out.println("Total time taken = " + time + " seconds.");
}
}
Explanation:
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}