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poizon [28]
2 years ago
7

Briefly discuss the aesthetics and ergonomics of a hydraulic jack. First explain what these

Computers and Technology
1 answer:
ehidna [41]2 years ago
5 0

Answer:

For this model, aesthetics is defined as a measure of how attractive a product appears, and ergonomics is how well a product feels when used/held. ... Two important types of defects, part flash and crush, will be used to define ergonomic and aesthetic PA's, respectively.

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The intention of this problem is to analyze a user input word, and display the letter that it starts with (book → B).
yulyashka [42]

Answer:

Here is the C++ program:

#include<iostream>  // to use input output functions

using namespace std;     //to identify objects like cin cout

void StartChar(string str)  {  // function that takes a word string as parameter and returns the first letter of that word in capital

   int i;  

   char c;

   do  //start of do while loop

   {

   for (int i = 0; i < str.length(); i++) {  //iterates through each character of the word str

       if(str.length()>25){  //checks if the length of input word is greater than 25

           cout<<"limit exceeded"; }  //displays this message if a word is more than 25 characters long

      c = str.at(i);   // returns the character at position i

       if (! ( ( c >= 'a' && c <= 'z' ) || ( c >= 'A' && c <= 'Z' ) ) ) {  //checks if the input word is contains characters other than the alphabet

            cout<<str<<" is not a word!"<<endl; break;}  //displays this message if user enters characters other than the alphabet

        if (i == 0) {  //check the first character of the input word

           str[i]=toupper(str[i]);  //converts the first character of the input word to uppercase

           cout<<str<<" starts with letter "<<str[i]<<endl;  }  // prints the letter that the word starts with in capital letter

   }   cout<<"Enter a word: ";  //prompts user to enter a word

      cin>>str;   //reads input word from user

}while(str!="#");   }    //keeps prompting user to enter a word until the user enters #

int main()   //start of the main() function body

{ string str;  //declares a variable to hold a word

cout<<"Enter a word: "; //prompts user to enter a word

cin>>str; //reads input word from user

   StartChar(str); }  //calls function passing the word to it

     

Explanation:

The program prompts the user to enter a word and then calls StartChar(str) method by passing the word to the function.

The function StartChar() takes that word string as argument.

do while loop starts. The for loop inside do while loop iterates through each character of the word string.

First if condition checks if the length of the input word is greater than 25 using length() method which returns the length of the str. For example user inputs "aaaaaaaaaaaaaaaaaaaaaaaaaaa". Then the message limit exceeded is printed on the screen if this if condition evaluates to true.

second if condition checks if the user enters anything except the alphabet character to form a  word. For example user $500. If this condition evaluates to true then the message $500 is not a word! is printed on the screen.

Third if condition checks if the first character of input word, convert that character to capital using toupper() method and prints the first letter of the str word in capital. For example if input word is "Computer" then this prints the message: Computer starts with the letter C in the output screen.

The program keeps prompting the user to enter the word until the user enters a hash # to end the program.

The output of the program is attached.

3 0
3 years ago
If you want to change the speed of a layer's horizontal scrolling, what should you change?
kirill [66]

Answer: A; X coefficient

Explanation: Hope I helped out !

-Carrie

Ps. it would mean a lot if you marked brainliest

6 0
3 years ago
A _______ is used to analyze and summarize your data without graphical support. A. PivotChart B. PivotTable C. chart D. table
Norma-Jean [14]
B. pivot table................................................
3 0
3 years ago
Markup is BEST defined as:
Finger [1]
The amount of money added to the product by the seller, difference between the cost price and selling price 
6 0
3 years ago
It is a well-researched fact that men in a restroom generally prefer to maximizetheir distance from already occupied stalls, by
Artyom0805 [142]

Answer:

The code below addresses the problem statement with appropriate comments for explanation.

Explanation:

public class Stall

{

public static void main(String[] args)

{

boolean[] arr = new boolean[10];

while(hasFreeSpots(arr))   // as long as there is a free slot

{

arr[position(arr)] = true;  

// position(arr) gets the position of slot a person would most likely enter at(view problem statement)

// setting that position true(position occupied) by arr[position(arr)]

System.out.println(stallView(arr));   // printing current state of the stall using 'X' and '_'

}

}

/**

* Find the empty position that is in the middle of the sub-array of largest group of empty spots

* @param arr an array of boolean values

* @return returns an an integer value. Optimal position to be occupied.

*/

public static int position(boolean[] arr)

{

int first = 0;   // first stores the starting position of "longest sequence of unoccupied places"

int last = 0;   // last stores the ending position of "longest sequence of unoccupied places"

int temp1 = 0;   // temp1 stores the starting position of "current sequence of unoccupied places"

int temp2 = 0; // temp2 stores the ending position of "current sequence of unoccupied places"

 

for(int i = 0; i < arr.length; i++)   // for each slot in the Stall

{    

if(!arr[i]) // if slot i is not occupied

{    

temp1 = i;   // store starting position of "current sequence of unoccupied places" in temp1

while(i < arr.length && !arr[i] )   // if i is a valid index and as long as this slot is not occupied increment i

{

i++;

}

// we break out of the loop either if i is invalid index(reached end of the array)

// or if the slot is occupied by a person already

temp2 = i;   // store ending position of "current sequence of unoccupied places" in temp2

if(Math.abs(first - last) < Math.abs(temp1 - temp2))

  // if current sequence is longer than longest sequence, update it

{

first = temp1;

last = temp2;    

}

}

}

return (first + last) / 2;   // return middle index of first and last

}

/**

* Checks if there are empty spots in an array, basically checks if there is a false boolean value

* thats representing an empty spot in an array

* @param arr the input array, of boolean values

* @return returns a boolean value, true if there are false elements inside the array

*/

public static boolean hasFreeSpots(boolean[] arr)

{

boolean rtn = true;   // initializing rtn to 'true'

for(int i = 0; i < arr.length; i++)   // for every slot in the Stall

{

if(!arr[i]){rtn = false;}   // sets rtn to false if a free spot found

}

return !rtn;   // returns true if a free spot found and returns false if no free spot found

}

/**

* X for true, _ for false. Representing occupied(X) and free stalls(_)

* @param arr a boolean array

* @return returns a string representation if the input

*/

public static String stallView(boolean[] arr)

{

String str = "";       // initializing str to be an empty String

for(int i = 0; i < arr.length; i++)   // for every slot in Stall

{

if(arr[i]){str += " X";}   // Add X to str if slot is occupied

else {str += " _";}           // prints _ to str if slot not occupied

}

return str;       // return str(pictorial representation of Stall with 'X', '_')

}

}

7 0
2 years ago
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