3 years ago

What is the equation of the line containing points (-4,3) and (7,5)

Mathematics

1 answer:

ki77a [65]3 years ago

3 0

Use the slope formula and slope-intercept form
y=mx+b
to find the equation.
y=2/11x + 4/11

Hope this helps

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Which of the following is an equation of the line that passes through the point (−2, 3) and is perpendicular to the graph of the

Ludmilka [50]

The equation of the line is $y=-\frac{1}{3}+\frac{7}{3}$

Explanation:

The given equation is $y=3 x-2$

<u>Slope:</u>

Since, the equation of the line is perpendicular to the equation $y=3 x-2$ , then, the slope is given by

$m=-\frac{1}{3}$

Hence, the slope is $m=-\frac{1}{3}$

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The equation of the line can be determined using the formula,

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Substituting the point (-2,3) and the slope $m=-\frac{1}{3}$ , in the above formula, we get,

$y-3=-\frac{1}{3}(x+2)$

Simplifying, we get,

$y-3=-\frac{1}{3}x-\frac{2}{3}$

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$y=-\frac{1}{3}+\frac{7}{3}$

Therefore, the equation of the line is $y=-\frac{1}{3}+\frac{7}{3}$

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