$f(x)=\dfrac{x-3}{x},\ D_f:x\neq0\\\\g(x)=5x-3,\ D_g=\mathbb{R}\\\\(f\cdot g)(x)=f(x)\cdot g(x)\\\\(f\cdot g)(x)=\dfrac{x-3}{x}\cdot(5x-3)=\dfrac{(x-3)(5x-3)}{x}\\\\D_{(f\cdot g)}=D_f$

Answer: The domain of (f•g)(x) is all real numbers except for 0

$D=\mathbb{R}-\{0\}$

4 0

2 years ago

WHAT IS FOURTH OFR 17%

kow [346]

0.0425 is a fourth of 17%

5 0

2 years ago

PLEASE HELP ME ON THIS QUESTION I DONT GET IT

nikdorinn [45]

The GCF is the first answer

4 0

2 years ago

What is 1/3 of 100%?

Andrej [43]

33.3333333333333333333333333333333333333(goes on forever)

7 0

2 years ago