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brilliants [131]
3 years ago
9

Roberto rented a truck from the Super Truck Company for 9 hours. There was a rental fee of $50. Allison rented a truck from Truc

king America for 4 hours. She paid a $110 rental fee. Both Roberto and Allison spent the same amount and both companies have the same hourly rental fee. Write and solve an equation to determine the hourly rental fee.
Mathematics
1 answer:
gavmur [86]3 years ago
4 0

Answer:

Hence, the hourly rental fee is \$\: 12.

Step-by-step explanation:

Time for which Roberto rented the truck =9 hours.

Rental fee =\$ \:50

Time for which Allison rented the truck =4 hours.

Rental fee =\$ \:110

Both companies have the same hourly rental fee.

Let the hourly rental fee of both the companies be x.

Both spent the same amount.

So, according to the question,

\Rightarrow 50+9x=110+4x

\Rightarrow 9x-4x=110-50

\Rightarrow 5x=60

\Rightarrow x=\frac{60}{5}

\Rightarrow x=12

Hence, the hourly rental fee is \$\: 12.

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g An urn contains 150 white balls and 50 black balls. Four balls are drawn at random one at a time. Determine the probability th
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Step-by-step explanation:

For sampling with replacement, we use the binomial distribution. Without replacement, we use the hypergeometric distribution.

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The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Sampling with replacement:

I consider a success choosing a black ball, so p = \frac{50}{150+50} = \frac{50}{200} = 0.25

We want 2 black balls and 2 white, 2 + 2 = 4, so n = 4, and we want P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.25)^{2}.(0.75)^{2} = 0.2109

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Sampling without replacement:

150 + 50 = 200 total balls, so N = 200

Sample of 4, so n = 4

50 are black, so k = 50

We want P(X = 2).

P(X = 2) = h(2,200,4,50) = \frac{C_{50,2}*C_{150,2}}{C_{200,4}} = 0.2116

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

3 0
3 years ago
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