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3 years ago

The steps below show the incomplete solution to find the value of n for the equation 4n − 2n + 4 = −1 + 17:

Mathematics

2 answers:

AlladinOne [14]3 years ago

7 0

Answer:

2n = 12

Step-by-step explanation:

4n-2n+4 = -1+17

add -1 and 17

4n-2n + 4 = 16

combine like terns

2n+ 4 = 16

subtract 4 from each side

2n+4-4 = 16-4

2n - 12

MrRissso [65]3 years ago

5 0

Answer:

(A) $2n=12$

Step-by-step explanation:

The given equation is:

$4n-2n+4=-1+17$

Solving the above equation, we get

Step 1. $4n-2n+4=-1+17$

solving the RHS of the above equation, we get

Step 2. $4n-2n+4=16$

Solving the LHs of the above equation, we get

Step 3. $2n+4=16$

Step 4. $2n=12$

⇒ $n=6$

Therefore, the value of n is $6$ and teh next step is $2n=12$ .

Hence, option (A) is correct.

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Answer:

Kindly check explanation

Step-by-step explanation:

Since the triangle is right angled ; we can solve for x using Pythagoras :

x = hypotenus ; hence ;

x² = opposite² + adjacent²

x² = 15² + 8²

x² = 225 + 64

x² = 289

x = √289

x = 17

Using Trigonometry :

Sin D = side opposite D / hypotenus = 8/17

Cos D = side Adjacent D / hypotenus = 15 / 17

Tan D = side opposite D / Adjacent side = 8/15

Sin F = side opposite F / hypotenus = 15/17

Cos F = side Adjacent F / hypotenus = 8 / 17

Tan F = side opposite F / Adjacent side = 15/8

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3 years ago

The path a character takes to navigate a level of a video game is given in the following graph.

mylen [45]

The domain is the set of x values that has a corresponding y-values in a function or a graph.

The domain of the graph is: $-10 \le x \le 10$

From the graph (see attachment), we have the following observation

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The value x ends at 10 (represented by the slant line on the first quadrant)

These values can be represented as:

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So, the domain of x is: $-10 \le x \le 10$

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3 years ago

Consider the function <br>f(x) = 8x^3 +1.<br><br> If f(g(x)) = x and g(f(x)) = x , find g(x) ?

Elena L [17]

$g( \: f(x) \: ) = x$

And

$f( \: g(x) \: ) = x$ _________________________________

So :

$g(x) = {f}^{ - 1}(x)$

And

$f(x) = {g}^{ - 1}(x)$

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So to find g(x) , we must find the inverse of f(x) .

Let's do it .....

$f(x) = 8 {x}^{3} + 1$

$y = 8 {x}^{3} + 1$

Subtract the sides of the equation minus 1

$y - 1 = 8 {x}^{3}$

Divided the sides of the equation by 8

$\frac{y - 1}{8} = {x}^{3} \\$

From the sides of the equation, we take the radical with interval 3

$\sqrt[3]{ \frac{y - 1}{8} } = x \\$

$\sqrt[3]{ \frac{1}{8}(y - 1) } = x \\$

$\frac{1}{2} \sqrt[3]{y - 1} = x \\$

$\frac{ \sqrt[3]{y - 1} }{2} = x \\$

So ;

${f}^{ - 1}(x) = \frac{ \sqrt[3]{x - 1} }{2} \\$

Now we find g(x) which is :

$g(x) = \frac{ \sqrt[3]{x - 1} }{2} \\$

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3 years ago

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Margaret [11]

Answer

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Step-by-step explanation:

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ELEN [110]

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a (the length is twice the width)

Step-by-step explanation:

a(the length is twice the width)

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