Equation of the line is y=mx+b
the line passing through point (1;-2) so x=1 y=-2
m=-0.5 so put all these values in equetion and found value of b
-2=-0.5*1+b
-2=-0.5+b
b=-1.5
so equation of the line is y=-0.5x-1.5
Answer:
equation of the line is y=-0.5x-1.5
Answer:
(12,-8)
Step-by-step explanation:
scale factor is 4
(x,y)=(4x,4y)
(3,-2)=(12,-8)
Answer:
x = -7
Step-by-step explanation:
-1 + x = -8
x = -7
Answer:
133.33g
Step-by-step explanation:
Let the:
Mass of 1.2g/cm³ of liquid = x
Mass of 1.8g/cm³ of liquid = y
From our Question above, our system of equations is given as:
x + y = 400........ Equation 1
x = 400 - y
1.2 × x + 1.8 × y = 1.6 × 400
1.2x + 1.8y = 640..... Equation 2
We substitute, 400 - y for x in Equation 2
1.2(400 - y) + 1.8y = 640
480 - 1.2y + 1.8y = 640
- 1.2y + 1.8y = 640 - 480
0.6y = 160
y = 160/0.6y
y = 266.67 g
Solving for x
x = 400 - y
x = 400 - 266.67g
x = 133.33g
Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g
