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blondinia [14]
3 years ago
8

PLEASE HELP ITS AN EMERGENCYYYYYYYYYY!!!

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0

Answer:

The value of k is 1.

Step-by-step explanation:

x – 1 is a factor of f(x)

This means that:

x - 1 = 0

x = 1

That means that when x = 1, y = 0. We use this to find the value of k.

f(x) = 3x^3 - 4x + k

3*1^3 - 4(1) + k = 0

3 - 4 + k = 0

k = 1

The value of k is 1.

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loris [4]

Answer:

Step-by-step explanation:

Solution

This (after combining the top 2 fractions, is a 4 tier fraction.

1/4*3/4 = 3/16

So the question now becomes 3/16 ÷ 10/3

The rule for such a question is invert (turn up side down) the second fraction and multiply.

3/16 * 3/10                   Combine

(3*3)/(16* 10)          

9 / 160

0.05625

6 0
2 years ago
Read 2 more answers
Someone help please.
AnnyKZ [126]

Answer:

Translation (the +5)

Dilation (the x 4)

Compression (the 3 to 1/3, and the x to 2-x)

Step-by-step explanation:

Brainliest, please!

5 0
3 years ago
HELP ASAP HURRY HURRY
mojhsa [17]
GIRL UHH TRY USING SOCRATIC HOLD ON
3 0
3 years ago
Read 2 more answers
2 times x plus x plus 45 =180
NARA [144]

Answer:

x= 45

Step-by-step explanation:

2x+x + 45 = 180

Combine like terms

3x+45 =180

subtract 45 from each side

3x+45-45= 180-45

3x = 135

Divide each side by 3

3x/3 = 135/3

x = 45

7 0
3 years ago
At the end of each quarter, Patti deposits $500 into an account that pays 12% interest compounded quarterly. How much will Patti
SVEN [57.7K]

Answer:

a.$7,096

Step-by-step explanation:

  • total amount A =  s(\frac{(1+\frac{r}{n}) ^{n*t}-1 }{\frac{r}{n} } )[/tex]

[this is the formula used when certain amount is added at regular intervals and if the interest is COMPOUNDED]

(here,

s=deposit added at the end of each quarter=  $500

n= number of times interest is compounded per unit 't'=4

t=total time = 3 years

r=interest rate ( expressed in decimal or fraction not in %) = 12/100 = 0.12 )

  • A= 500(\frac{(1+\frac{0.12}{4}) ^{4*3}-1 }{\frac{0.12}{4} } )[/tex]
  • by solving further,

A  =500(\frac{(1.03) ^{12}-1 }{0.03} )\\\\=500(\frac{1.42576-1}{0.03} )\\\\=500(\frac{0.42576}{0.03}) \\=$7,096

( [1.03]^12= 1.42576 ( approximately) { use calculator for exact values})

3 0
3 years ago
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