All categories

2 years ago

A quarter has a diameter of 2.4 centimeters. What is the area of the coin (round answer to nearest tenth)?

Mathematics

1 answer:

mafiozo [28]2 years ago

4 0

Answer:

4.5

Step-by-step explanation:

The equation of an area of a circle is A=πr² where r is the radius.

The radius is also half the diameter. So the radius of the quarter is 1.2

A=π(1.2)²

A=π(1.44)

A=4.52389

You might be interested in

Will select brainliest if ur answer is correct

ella [17]

Answer:

B (I think)

Step-by-step explanation:

A function can't have two X values that are the same (If I remember correctly) and the second table is the only one that doesn't have duplicated X values

6 0

2 years ago

Read 2 more answers

A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m

Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

Let the weight of first alloy used be $x$ in pounds and the weight of second alloy used be $y$ in pounds.

Total weight = $46\text{ }pounds=x+y$ $-(i)$

Total weight of copper = $37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }$

$\dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702$ $-(ii)$

Subtracting 34 times first equation from second equation,

$34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds$

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0

2 years ago

Plz i need help am i am new an plz help help

Dafna11 [192]

Answer:

5) 64

3) a loaf of bread

6) 2

4) see saw

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Plzzzzzzzz help fast im slow

zmey [24]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Diagram 5 shows a triangle ABD such that AD = 17 cm, AB = 10 cm and BD = 21 cm. The straight line AC is perpendicular to the str

OlgaM077 [116]

Answer:

Step-by-step explanation:

100 = x^2 + AC^2

17^2 = AC^2 + (21 - x)^2

289 = AC^2 + 21^2 + x^2 - 2*21*x

289 =<u> AC^2</u> + 441 +<u> x^2</u> - 42x

from 1st equation AC^2 + x^2 = 100

289 = 441 + 100 - 42x

289 = 541 - 42x

42x = 541 - 289 = 252

x = 252/42 = 6

so AC^2 = 100 - 6^2 = 100 - 36 = 64

AC = 8

7 0

2 years ago