Diagonal of a Rhombus are perpendicular & intersects in their middle point:
Assume the diagonals intersects in H
A(0,-8), B(1,-0), C(8,-4) & D(x, y) are the vertices of the rhombus and we have to calculate D(x, y)
Consider the diagonal AC. Find the coordinate (x₁, y₁) H, the middle of AC
Coordinate (x₁, y₁) of H, middle of A(0,-8), C(8,-4)
x₁ (0+8)/2 & y₁=(-8-4)/2 ==> H(4, -6)
Now let's calculate again the coordinate of H, middle of the diagonal BD
B(1,-0), D(x, y)
x value = (1+x)/2 & y value=(y+0)/2 ==> x= (1+x)/2 & y=y/2
(1+x)/2 & y/2 are the coordinate of the center H, already calculated, then:
H(4, -6) = [(1+x)/2 , y/2]==>(1+x)/2 =4 ==> x=7 & y/2 = -6 ==> y= -12
Hence the coordinates of the 4th vertex D(7, -12)
2 and 2/4 = 10/4
10/4 ÷ 1/4 = 10/4 × 4/1 = 10 cups
Parenthesis
exponents
multiplication/division
addition/subtraction
when given a math problem you must go through these operations from top to bottom to recieve the correct answer
Since we know a triangle only has 180 degrees we can say:
99+3x+x+5=180
Then we can solve for x:
4x+104=180
4x=76
x=19
Answer:
132cm2
Step-by-step explanation:
1. Split the figure into a trapezoid and a rectangle.
2. Find the area of the trapezoid, which is 104cm2.
3. Find the area of the rectangle, which is 28cm2.
4. Add the areas to get 132cm2.
