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2 years ago

The angles of a triangle are 99??, 3x??, and x + 5??.

1 answer:

3 0

Since we know a triangle only has 180 degrees we can say:

99+3x+x+5=180

Then we can solve for x:

4x+104=180
4x=76

x=19

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WHAT IS 4 TIMES TWO THIRDS IN A MIXED FRACTION

Alex73 [517]

$\frac{4}{1}$ × $\frac{2}{3}$ = $\frac{8}{3}$
You then divide the numerator(top) by the denominator(bottom)
$\frac{8}{3}$ = $2 \frac{2}{3}$
Your answer is $2 \frac{2}{3}$

3 0

3 years ago

Read 2 more answers

(NEED DONE SOON) The measure of two supplementary angles are 4x - 24 and 4(2x - 3). <br> What is x

Zarrin [17]

Answer:

x = 12

Step-by-step explanation:

A pair of supplementary angles added together MUST equal 180. Therefore, as you are given two angles with the measures of (4x - 24) and 4(2x - 3), they must add together to equal 180. So, we get this equation:

(4x - 24) + 4(2x - 3) = 180

4x - 24 + 8x - 12 = 180 (we distributed 4(2x-3))

12x - 36 = 180

12x = 144

x = 12, -12

Therefore, x is 12 because -12 would mean that (4x-24) and 4(2x-3) are both negative, which is impossible for an angle measure.

5 0

2 years ago

If the perimeter of the triangle is 73 mm, find the value of x.

Ipatiy [6.2K]

To find x, we simply need to subtract the sum of the other two sides from 73.
35+11=46
73-46=27

So x = 27mm

7 0

2 years ago

Study the following data set.

Katen [24]

The interquartile range of the data set is 8

<h3>How to solve for the interquartile range</h3>

To do this we have to arrange in ascending order

= 8,9,9,9,10,11,13,15,17,18,22

Q2 = The median of the data is 11.

We have to find the median of the half before 11 and the median of the half after 11.

We would have

8,9,9,9,10

Q1 = 9

And 13,15,17,18,22

Q3 = 17

The interquartile range is

Q3 - Q1

= 17 - 9

= 8

The interquartile range of the data set is 8