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3 years ago

I WILL REWARD BRAINLIEST

Mathematics

2 answers:

german3 years ago

6 0

D because it is bringing data from people almost able to make a graph or chart. Dot plot bar graph etc etc

aksik [14]3 years ago

4 0

Answer:

Answer: What is the total number of students who brought water bottles to lunch?

A statistical question is a question with data that will vary.

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Select three major processes that should be included in a model that explains the changes seen in the rock between figure 1 and

Arturiano [62]

Answer:

I think it's C and F. Don't depend on me tho I'm only in the 7th grade but I just told what I think is more logical

5 0

3 years ago

students are painting a mural so far the mural is painted 1/4 blue ,2/8 red and 3/12 green use fraction strips to determine how

Fofino [41]

------------------------------------------------------------------------------------
Reduced (simplify) all factions if possible
------------------------------------------------------------------------------------

(1/4 cannot be reduced)
1/4 = 1/4

(divided by 2 for both numerator and denominator)
2/8 = 1/4

(divide by 3 for both numerator and denominator)
3/12 = 1/4

------------------------------------------------------------------------------------
Find combined fraction of the mural that has been painted.
------------------------------------------------------------------------------------
1/4 + 1/4 + 1/4 = 3/4

------------------------------------------------------------------------------------
Answer: 3/4 of the mural has been painted.
------------------------------------------------------------------------------------

4 0

4 years ago

Who can help me d e f thanks

12345 [234]

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

2 years ago

Lena is 10 years old. She asks her dad how old he is. He tells her that the lcm of their ages is 14 times the hcf of their ages.

strojnjashka [21]

Answer:

Step-by-step explanation:

Let x represent the HCF of the ages. Then we can have ax = 10 represent Lena's age, and bx can represent her dad's age.

The LCM will be abx = 14x, so we have ab = 14.

Factors of 14 are 1·14 and 2·7. Since the ratio of ages is between 30/10 = 3 and 45/10 = 4.5, we must have b/a in that range. This will be the case for ...

a=2, b=7

For a=2 and ax=10, we have x=5.

The dad's age is bx = 7·5 = 35.

5 0

3 years ago

Plz solve thesessss plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

shepuryov [24]

Answer:

5.) b = -2/5 (or -0.4 in decimal form)

6.) 20.5

5 0

3 years ago

Read 2 more answers