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3 years ago

(1 point)

Mathematics

2 answers:

inn [45]3 years ago

5 0

22 ft below sea level

sergeinik [125]3 years ago

3 0

Answer:

22 feet below sea level

Step-by-step explanation:

she kept going down, basically in a negative way. adding to the already below sea level

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Solve for (x) x+15=3x+5

dolphi86 [110]

Answer:

$x + 15 = 3x + 5 \\ 15 - 5 = 3x - x \\ 10 = 2x \\ \frac{10}{2} = \frac{2x}{2} \\ x = 5$

hope this helps....

8 0

3 years ago

Find the solution set for x2 + 3x – 40 = 0.

Temka [501]

I am going to assume that x2 = x squared
So: X^2 + 3x -40
= (X+8)(X-5)=0

X+8 = 0
X= - 8

The other solution is X -5 = 0
X = 5

Therefore the solution set is {-8, 5}

8 0

3 years ago

HELPPPPPPPPPPPPPPPPWhich statements are true about the ordered pair(-1, -4) and the system of

Anastasy [175]

Answer:

When (-1,-4) is substituted into the second equation, the equation is true.

The ordered pair (-1,-4) is a solution to the system of linear equations.

When (-1,-4) is substituted into the first equation, the equation is true.

Step-by-step explanation:

Given

$x - y = 3$

$7x - y = -3$

Required

What is true about $(x,y) = (-1,-4)$

To do this, we substitute -1 for x and -4 for y in both equations;

For $x - y = 3$

$-1 - (-4) = 3$

$-1 + 4 = 3$

$3 = 3$

Hence: $(-1,-4)$ is true for $x - y = 3$

For $7x - y = -3$

$7(-1) - (-4) = -3$

$-7 +4 = -3$

$-3 = -3$

Hence: $(-1,-4)$ is true for $7x - y = -3$

3 0

3 years ago

Jennifer invested $3300 in a savings account with a yearly interest rate of 6% for 9 years. How much simple interest did she ear

givi [52]

It's $1782 for ApexApex. I tried the A but it was wrong

5 0

3 years ago

A circle has a diameter 9 cm.

vredina [299]

Answer:

Step-by-step explanation:

Since we are to show by Pythagoras that the square will fit inside the circle without touching the edge of the circle , this means that we must find the value of the length of the diagonal of the square using Pythagoras.

For the square to fit in without touching the edge of the circle , this means that the diagonal of the square must be less than the diameter of the circle.

Length of the square is 5cm.

Recall Pythagoras theorem: it states that

the square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides

$D^{2}$ = $5^{2}$ + $5^{2}$

$D^{2}$ = 25 + 25

$D^{2}$ = 50

Take the square root of both sides , that is

D = $\sqrt{50}$

D = $\sqrt{25}$ X $\sqrt{2}$ , since 50 = 25 x 2

D = 5 $\sqrt{2}$

D ≈ 7.07

Note that the diameter of the circle given is 9 and D < 9 , we can therefore conclude that the square will fit inside the circle without touching the edge of the circle since the diagonal of the square is less than the diameter of the circle

8 0

3 years ago