Answer:
a) Right 0≤p<π/2 and 3π/2<p≤2π
left π/2 ≤ p ≤3π/2
stopped p=π/2 and p=3π/2
b) 5.5cm and its final position (2π, 0)
c) 6.5cm
Step-by-step explanation:
we must find where the function becomes negative, positive and zero
(according to the graph)
the particle moves to the right where the function is positive
0≤p<π/2 and 3π/2<p≤2π , the particle moves to the left where the function is negative π/2 ≤ p ≤3π/2, and stopped p=π/2 and p=3π/2
s(t)=∫v(t)dt also s(t) = 5sin(t)
(according to the graph 2)
The displacement of the particle is 5.5 and its final position
(2π, 0)
The total displacement of the particle is 6.5
You take the length times the width to get the area.
Find the distance between the points to the nearest tenth.
1. C(-1, -1), D(6, 2)
<h3>= 7.6</h3>
2. E(-7, 0), F(5 ,8)
=3(3.6)
<h3>=10.8</h3>
______________________________________________________
AB has endpoints A(-3, 2) and B(3, -2).
3. find the coordinates of the midpoint of Line AB
4. Find AB to the nearest tenth
<h3>
AB = 7.2 units.</h3>
Answer:
8
Step-by-step explanation:
32 + 72 = __(4 + 9)
The greatest common factor of 32 and 72 is 8.
Divide 32 by 8. Divide 72 by 8.
Plug in 8 for the blank space.
32 + 72 = _8_(4 + 9)
Hope this helps!
5 is the independent variable and 20.0 is the dependent variable.