2 years ago

If the equation of a circle is (x+5)^2 + (y-7)^2=36, its center point is

Mathematics

1 answer:

BigorU [14]2 years ago

3 0

Answer:

centre = (- 5, 7 )

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 5)² + (y - 7)² = 36 ← is in standard form

with h = - 5 and k = 7

centre = (- 5, 7)

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If the equation of a circle is (x+5)^2 + (y-7)^2=36, its center point is​

If the equation of a circle is (x+5)^2 + (y-7)^2=36, its center point is