Answer:
the present age of the father be x and the present age of the son be y.
It is given that man is 24 years older than his son that is:
x=y+24
x−y=24..........(1)
Also, 12 years ago, he was five times as old as his son that is:
(x−12)=5(y−12)
x−12=5y−60
x−5y=−60+12
x−5y=−48..........(2)
Now subtract equation 1 from equation 2 to eliminate x, because the coefficients of x are same. So, we get
(x−x)+(−5y+y)=−24−48
i.e. −4y=−72
i.e. y=18
Substituting this value of y in (1), we get
x−18=24
i.e. x=24+18=42
Hence, the present age of the father is 42 years and the present age of the son is 18 years.
Step-by-step explanation:
Answer:
7 weeks
Step-by-step explanation:
130-4 = 126
126÷18=7
The points for this graph are (3,0) and (0,2). Looking at the point to the right, you go left or right before you go up and down. You first go to the right 3 times, but you don't go up or down. So this point is (3,0). Looking at the next point you don't go left or right at all, but you do go up two spaces, so this point is (0,2).
If the area is 836 square feet and its length is 38 feet, the width will be 22ft.
