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elena-s [515]
2 years ago
10

Consider the equation. 35 + = 7(5+3)

Mathematics
1 answer:
Deffense [45]2 years ago
6 0

Answer:

21

Step-by-step explanation:

35+? = 7(5+3)

35+? = 7(8)

35+? = 56

? = 56-35

? = 21

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mars1129 [50]

Answer:

Your answer is

tangent ratio of B is 3/2

Mark my answer as brainlist . I need that urgently . Folow me for more answer.

Step-by-step explanation:

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A cylinder has a base radius of 4m and a height of 6m. What is its volume in cubic m,
BlackZzzverrR [31]

Answer:

301.4

Step-by-step explanation:

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Since you want to round to nearest tenths, the answer is 301.4

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A model giraffe has a scale of 1 in : 3 ft. If the model giraffe is 4 in tall, then how tall is the real giraffe
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4 0
3 years ago
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First line joins ordered pairs negative 4, 3 and 2, negative 3. Second line joins negative 4, negative 3 and 2, 3. Part A shaded
elena55 [62]

The part that represents the solution to the inequality will be Part B shaded below first line and above second line.

<h3>How to depict the inequality?</h3>

From the information given, the equation of the first line will be:

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y - 3 = -1(x + 4)

y + x = -4 + 3

x + y = -1

The equation of the second line will be:

y + 3 = -1(x + 4)

y = x + 4 - 3

y = x + 1

This is plotted on the graph attached.

From the systems of equations, the statement that is correct about the two systems of equations is that They will have the same solution because the first equation of System B is obtained by adding the first equation of System A to 3 times the second equation of System A.

Learn more about inequalities on:

brainly.com/question/12215820

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4 0
2 years ago
ALGEBRA 2!!!!!!!!! SHOW YOUR WORK!!!!!!!!!!!!!<br> Do f(g(x)) and g(f(x))
bezimeni [28]

\bf f(x)=\cfrac{2x-3}{x+1}~\hspace{10em}g(x)=\cfrac{x+3}{2-x}&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;f(~~g(x)~~)\implies \cfrac{2[g(x)]-3}{[g(x)]+1}\implies \cfrac{2\left( \frac{x+3}{2-x} \right)-3}{\left( \frac{x+3}{2-x} \right)+1}\implies&#10;\cfrac{\frac{2x+6}{2-x}-3}{\frac{x+3}{2-x}+1}&#10;\\\\\\&#10;\cfrac{\frac{2x+6-6+3x}{2-x}}{\frac{x+3+2-x}{2-x}}\implies \cfrac{2x+6-6+3x}{2-x}\cdot \cfrac{2-x}{x+3+2-x}\implies \cfrac{5x}{5}\implies x


\bf \rule{34em}{0.25pt}\\\\&#10;g(~~f(x)~~)\implies \cfrac{[f(x)]+3}{2-[f(x)]}\implies \cfrac{\frac{2x-3}{x+1}+3}{2-\frac{2x-3}{x+1}}\implies \cfrac{\frac{2x-3+3x+3}{x+1}}{\frac{2x+2-(2x-3)}{x+1}}&#10;\\\\\\&#10;\cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-(2x-3)}\implies \cfrac{2x-3+3x+3}{x+1}\cdot \cfrac{x+1}{2x+2-2x+3}&#10;\\\\\\&#10;\cfrac{5x}{5}\implies x


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4 0
3 years ago
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