The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:
Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Sam is at 23 feet below the surface
Explanation
I did 14+9 and got 23
Answer: -3x^3 - 7x^2 - x + 39
Step-by-step explanation:
2/(x^2 -9) - 3x/(x^2-5x+6)
get those denominators factored out
2/(x-3)(x+3) - 3x/(x-3)(x-2)
Multiply both by both denominators
2(x-3)(x-2) - 3x(x-3)(x+3)
Multiply it out
(2x^2 - 10x + 12) - (3x^3 + 9x^2 -9x - 27)
Simplify and it becomes
-3x^3 -7x^2 -x + 39
Answer:
Fourth root of 256 is ±4.
hope this helps