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3 years ago

Can you PLEASE answer number 16 and 18!

Mathematics

2 answers:

xeze [42]3 years ago

7 0

For 18 I think it’s A :)

Lorico [155]3 years ago

3 0

Answer:

number 16 is c

y = 5x + 8

y = 5(-6) + 8

y = -30 + 8

y = -22

y = 5(-3) + 8

y= -15 + 8

y = -7

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Monica bought a new house and she is looking to get cable and wifi. She is looking for reasonable prices. Monica is trying to co

nadezda [96]

Answer:

I think she should get the Verizon house hold Wifi because when you compare the prices even if Monica doesn't want any extra channels she would still save $15. Even tho the extra channel was $4 for the Comcast when you add it up you get $64 instead when you use Verizon even tho you pay $6 for extra channels you still don't get the amount for the Comcast which you save $13 by getting Verizon with $51.

Step-by-step explanation:

3 0

3 years ago

I need to answer 1-10 and do not understand. They are conversions and double conversions. This is math and I have a test

jok3333 [9.3K]

1.) 421.307
2.)12.778
3.)16
4.)106.25
5.) 271.17
6.) 4136.96
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5 0

3 years ago

Colin and Brian were playing darts. Colin scored 139 Brian scored 53 more than Colin. What was their combined score?

Inga [223]

Answer

Their combined score is 331 points

Explanation

Determine each person's score

Collin score: 139

Brian: 139 + 53 = 192

Add the scores together

139 + 192 = 331

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20k%20-%20%28k%20%2B%20%20%5Cfrac%7B1%7D%7B4%7D%29%20%3D%20%20%5Cfrac

VikaD [51]

Firstly, foil -(k + 1/4) (think of the minus sign as -1):

$\frac{2}{3}k-k-\frac{1}{4}=\frac{1}{12}k+\frac{4}{12}$

Next, combine like terms:

$-\frac{1}{3}k-\frac{1}{4}=\frac{1}{12}k+\frac{4}{12}$

Next, we have to add 1/3k on both sides, but first we have to find the LCD, or lowest common denominator, of 3 and 12. To do this, list the multiples of both and the lowest one they share is their LCD. In this case, the LCD is 12. Multiply both sides of -1/3 by 4/4 and 1/12 by 1/1:

$-\frac{1}{3}\times \frac{4}{4}=-\frac{4}{12}\\\\\frac{1}{12}\times \frac{1}{1}=\frac{1}{12}\\\\-\frac{4}{12}k-\frac{1}{4}=\frac{1}{12}k+\frac{4}{12}$

Now add 4/12k on both sides of the equation:

$-\frac{1}{4}=\frac{5}{12}k+\frac{4}{12}$

Next, to subtract 4/12 on both sides we need to find the LCD of 4 and 12. It's the similar process as we did with 12 and 3. This time the LCD is also 12. Multiply both sides of -1/4 by 3/3 and 4/12 by 1/1:

$-\frac{1}{4}\times \frac{3}{3}=-\frac{3}{12}\\\\\frac{4}{12}\times \frac{1}{1}=\frac{4}{12}\\\\-\frac{3}{12}=\frac{5}{12}k+\frac{4}{12}$