Answer:
C
Step-by-step explanation:
Given 2 secants intersect a circle from a point outside the circle, then
The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is
x(x + 10 + x) = 6(6 + 10 + x)
x(2x + 10) = 6(16 + x) ← distribute parenthesis on both sides
2x² + 10x = 96 + 6x ← subtract 96 + 6x from both sides
2x² + 4x - 96 = 0 ← in standard form
Divide through by 2
x² + 2x - 48 = 0 ← factor the left side
(x + 8)(x - 6) = 0
Equate each factor to zero and solve for x
x + 8 = 0 ⇒ x = - 8
x - 6 = 0 ⇒ x = 6
However x > 0 ⇒ x = 6 → C
5 the answer I took the test
The right answer is 6x + 5
The Pythagorean Theorem states that a triangle's hypotenuse is equal to the square's of the other two sides of the triangle.
a² + b² = c<span>²
a = side of triangle
b = other side of triangle
c = hypotenuse (squared)
Find the square root to find the accurate length of the hypotenuse.</span>
Answer:
A
Step-by-step explanation:
I am not sure though. Sorry if it is wrong :(
