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3 years ago

I need help rn please

Mathematics

1 answer:

nirvana33 [79]3 years ago

8 0

Hello!

$\large\boxed{\text{ slope = -3}}$

Use the slope formula to solve for the slope of the line (m):

$m = \frac{y^{2} -y^{1} }{x^{2} -x^{1} }$

We can plug in the points (0, 4) and (1, 1) to solve:

$m = \frac{1-4}{1-0}= \frac{-3}{1} = -3$

Therefore, the slope of the line is -3.

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4 years ago

Pls help me solve this question, also include step by step calculation ya. Thks

sp2606 [1]

$\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}$

Step-by-step explanation:

$5x^2-x^2e^{2x}+2e^{2x}=10$

$Let:\ x^2=t \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}$

Prologarithmize both parts of the equation:

$ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\$

Divide both parts of the equation by 2:

$\displaystyle\\x=\frac{ln5}{2}$

$t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}$

6 0

1 year ago

I need help rn please​

I need help rn please