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3 years ago

Need Assistance ASAP!

Mathematics

1 answer:

Kitty [74]3 years ago

3 0

Answer:

4 = $8

6 = $12

9 = $18

10 = $20

Explanation:

Well if there are three tickets and the cost is six dollars then all you are doing is multiplying by two.

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What is (1.2 × 102) × (3 × 10–5)?

fgiga [73]

The answer for this question is the letter B

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3 years ago

Use the rule (x,y) (3x,2y) to find the image for the preimage defined by the given points.

Elina [12.6K]

Answer: The points of the images are (9,10), (15,6), (6,4) and the image is not a rigid motion because the shape changes in side.

Step-by-step explanation:

Since it gives you the scale factor then find they coordinates by multiplying the coordinates by the scare factor.

A(3,5) → (3*3,5*2) → (9,10)

B( 5,3) → (5*3, 3*2) → (15,6)

C ( 2,3)→ (2*3, 2*2)→ ( 6,4)

4 0

4 years ago

PLEASE HELP ME ASAP!!!! ILL MARK BRIANLIEST AND GIVE EXTRA POINTS

kumpel [21]

Answer:

b > 250/9 and w ≥ 0

Step-by-step explanation:

7/9 (b - 27) > 49/81

First, simplify both sides of the inequality:

7/9b - 21 > 49/81

Add 21 to both sides

7/9b - 21 +21 > 49/81 +21

Multiply both sides by 9/7

9/7 x 7/9b > 49/81 x 9/7

b > 1750/81

Simplify

b > 250/9

11w - 8w ≥ 14w

Simplify both sides once again

3w ≥ 14w

Subtract 14w from both sides

3w - 14w ≥ 14w - 14w

-11w ≥ 0

Divide both sides by -11w

w ≥ 0

3 0

3 years ago

Read 2 more answers

Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid

Gnom [1K]

Answer:

The area of the triangle is $A=\sqrt{\frac{4027}{2}}$

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

$A=\frac{1}{2}||{\bf u} \times {\bf v} ||$

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

${\bf AB}$ and ${\bf AC}$

The vector ${\bf AB}$ is the difference of point B minus point A

${\bf AB}=(5-3,5-5,0-9)=(2,0,-9)$

and the vector ${\bf AC}$ is the difference of point C minus point A

${\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)$

Next we need to find the cross product of this vectors.

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

This is the definition of cross product of two vectors in space:

Let ${\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k}$ and ${\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k}$ be vectors in space. The cross product of ${\bf u}$ and ${\bf v}$ is the vector

${\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}$

Applying this definition we get

${\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}$

$\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}$

$||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}$

The area of the triangle is

$A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}$

7 0

4 years ago

6(3u+4) please help I am in a classwork

frozen [14]

Answer:

18u+24

Step-by-step explanation:hope this helps xxx

7 0

3 years ago