Answer:
0.44
Step-by-step explanation:
See the picture below.
Remember that the sine is the ratio of the length of the opposite leg to the length of the hypotenuse.
Perhaps you know SOHCAHTOA, where SOH means sine, opposite, hypotenuse.
For angle J, leg LK is the opposite leg.
The hypotenuse of the triangle is the side opposite the right angle, teh angle of 90°, which is angle L, so the hypotenuse is side KJ.
Answer: 0.44
Answer:
(A+B)(A+B)=A.A+B.A+A.B+B.B
Step-by-step explanation:
Given that matrices A and B are nxn matrices
We need to find (A+B)(A+B)
For understanding the multiplication of matrices let'take A is mxn and B is pxq matrices,we can multiple only when n=p,so our Ab matrices will be mxq.
We know that that in matrices AB is not equal to BA.
Now find
(A+B)(A+B)=A.A+B.A+A.B+B.B
So from we can say that (A+B)(A+B) is not equal to A.A+2B.A+B.B because AB is not equal to BA in matrices.
So (A+B)(A+B)=A.A+B.A+A.B+B.B
Answer:
-0.05
Step-by-step explanation:
Given the expression :
0.1×( – 0.9+ – 0.2÷ – 0.5)
Evaluating the bracket :
0.1 * (-0.9 - 0.2 ÷ - 0.5)
Solving the division first
-0.2 ÷ - 0.5 = 0.4
Now we have ;
0.1 * (-0.9 + 0.4)
0.1 * - 0.5
= - 0.05
Answer:
The answer to the system of equations is 4, -4
Solve the following system:{12 x = 54 - 6 y | (equation 1)-17 x = -6 y - 62 | (equation 2)
Express the system in standard form:{12 x + 6 y = 54 | (equation 1)-(17 x) + 6 y = -62 | (equation 2)
Swap equation 1 with equation 2:{-(17 x) + 6 y = -62 | (equation 1)12 x + 6 y = 54 | (equation 2)
Add 12/17 × (equation 1) to equation 2:{-(17 x) + 6 y = -62 | (equation 1)0 x+(174 y)/17 = 174/17 | (equation 2)
Multiply equation 2 by 17/174:{-(17 x) + 6 y = -62 | (equation 1)0 x+y = 1 | (equation 2)
Subtract 6 × (equation 2) from equation 1:{-(17 x)+0 y = -68 | (equation 1)0 x+y = 1 | (equation 2)
Divide equation 1 by -17:{x+0 y = 4 | (equation 1)0 x+y = 1 | (equation 2)
Collect results:Answer: {x = 4 {y = 1
Please note the { are supposed to span over both equations but it interfaces doesn't allow it. Please see attachment for clarification.
