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nignag [31]
3 years ago
11

What is sin 62°? 62 17 8 28° 90° 15 O A. B. O O c. O

Mathematics
2 answers:
stiv31 [10]3 years ago
8 0

Answer:

sin = opposite/hypotenuse.

the hypotenuse is 17, adjacent is 8 and opposite is 15

15/17 is sine of 62. (C is the correct answer.)

Step-by-step explanation:

barxatty [35]3 years ago
4 0

Answer:

The letter C. 15/17

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A student said that since –9 is less than 4, then |–9| is less than |4|. Is the student correct? Explain why or why not
Leno4ka [110]
The student is not correct.

Absolute value means distance from zero
|-9| = 9
|4| = 4

Since 9 is greater than 4,
|-9| is greater than |4|

In other words, -9 is further from zero then 4
5 0
3 years ago
Can someone please help me Factor 4x^2 - 81
Vsevolod [243]

Answer:

(2x-9)(2x+9)

Step-by-step explanation:

This is a difference of squares because it can be written as (2x)^2-9^2

The formula for factoring a difference of squares is a^2-b^2=(a-b)(a+b)

So replace a with 2x and b with 9 giving us

4x^2-81=(2x-9)(2x+9)

3 0
3 years ago
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Point H is between G and I. If HG = 8x + 7, HI = 3x - 2, and GI = 38, what would be the length of GH ?
AVprozaik [17]

Answer:

let's see what to do...

Step-by-step explanation:

H is between G and I.

G I = G H + H I

38 = 8 x + 7 + 3x - 2

38 = 11 x + 5

subtract the sides of equation minus 5

38 - 5 = 11 x + 5 - 5

33 = 11 x

divided the sides of equation by 11

33 ÷ 11 = 11 x ÷ 11

3 = x

So the lenght of (G H) is :

8 x + 7 -----¢ 8 (3) + 7 = 24 + 7 = 31

And we're done.

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8 0
3 years ago
WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!
Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: a^2-b^2=(a+b)(a-b)

Given  x^2-16=0

Rewrite 16 as 4²

Therefore, a^2=x^2 and b^2=4^2

\implies a = \sqrt{x^2}=x

\implies b=\sqrt{4^2} =4

\implies x^2-16^2=(x+4)(x-4)

\implies (x+4)(x-4)=0

\implies (x+4)=0 \implies x=-4

\implies (x-4)=0 \implies x=4

<u>Method 2</u>

Given equation:

x^2-16=0

Add 16 to both sides:

\implies x^2-16+16=0 + 16

\implies x^2=16

Square root both sides:

\implies \sqrt{x^2}=\sqrt{16}

\implies x=\pm4

Therefore, x = -4, x = 4

6 0
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Answer:

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Step-by-step explanation:

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