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3 years ago

6x² – x=2 Factor and solve

Mathematics

1 answer:

const2013 [10]3 years ago

5 0

Answer:

x=2/3 or x=−1/2

Step-by-step explanation:

6x²−x=2

6x²−x−2=2−2

6x²−x−2=0

(3x−2)(2x+1)=0

3x−2=0 or 2x+1=0

x=2/3 or x=−1/2

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What number gives a result of −4 when 10 is subtracted from the quotient of the number and 4?

Arisa [49]

Answer:

Step-by-step explanation:

8 0

2 years ago

Fred works as an

OLEGan [10]

Step-by-step explanation:

so he already down 20 ft so he ascends (goes up) 9 feet, so hes at 11 feet right now. then he descends 12 (goes down) feet so hes at 23 feet. lastly he ascends 15 feet (goes up) more. so the answer is 8

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3 years ago

Henry ran five races, each of which was a different positive integer number of

dolphi86 [110]

Answer:

10 miles.

Step-by-step explanation:

Let x be the number of miles on Henry's longest race.

We have been given that Henry ran five races, each of which was a different positive integer number of miles.

We can set an equation for the average of races as:

$\frac{\text{The sum distances of 5 races}}{5}=4$

As distance covered in each race is a different positive integer, so let his first four races be 1, 2, 3, 4.

Now let us substitute the distances of 5 races as:

$\frac{1+2+3+4+x}{5}=4$

$\frac{10+x}{5}=4$

Let us multiply both sides of our equation by 5.

$\frac{10+x}{5}*5=4*5$

$10+x=20$

Let us subtract 10 from both sides of our equation.

$10-10+x=20-10$

$x=10$

Therefore, the maximum possible distance of Henry's longest race is 10 miles.

7 0

3 years ago

(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw

slavikrds [6]

Answer:

a. $\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. $C_{0}=122$

c. $k=-0.00259$

d. $t=153.39838\\$ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

$Tm=68$

$\frac{dT}{dt}=k(T-Tm); T(0)=190$

b. The differential equation obtained is a differential equation of separable variables:

$\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122$