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Lostsunrise [7]
3 years ago
5

Use the following cell phone airport data speeds​ (Mbps) from a particular network. Find the percentile corresponding to the d

ata speed 11.2 Mbps. 0.1 0.2 0.2 0.3 0.4 0.4 0.4 0.5 0.5 0.6 0.6 0.8 0.9 0.9 0.9 1.1 1.3 1.7 1.8 1.9 2.3 2.4 2.5 2.6 2.7 3.1 3.5 3.5 3.7 3.8 4.8 5.2 7.4 7.9 8.2 8.6 9.3 11.2 11.3 11.4 12.1 12.6 13.1 13.3 13.6 13.8 14.6 15.6 15.7 25.6
Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer: the percentile is 74%

Step-by-step explanation:

The given data distribution is arranged in increasing order as:

0.1 0.2 0.2 0.3 0.4 0.4 0.4 0.5 0.5 0.6 0.6 0.8 0.9 0.9 0.9 1.1 1.3 1.7 1.8 1.9 2.3 2.4 2.5 2.6 2.7 3.1 3.5 3.5 3.7 3.8 4.8 5.2 7.4 7.9 8.2 8.6 9.3 11.2 11.3 11.4 12.1 12.6 13.1 13.3 13.6 13.8 14.6 15.6 15.7 25.6

The total number of values given in the data is 50

Percentile = number of values in the distribution lesser than the given value × 100/ total number of values in the distribution

Considering the data speed of 11.2 Mbps, the number of data speed lower than 11.2 is 37

Percentile = (37 × 100)/50 = 74%

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Joshua's goal is to sell more than 20 items at a farmers' market. So far, he has sold 6 items. Each of his customers buys 2 item
amid [387]

Answer:

More than 7

Step-by-step explanation:

Given that:

Joshua's goal is to sell more than 20 items at a farmer's market.

Number of items already sold = 6

So, number of more items to be sold > Total number of items to be sold - Number of items already sold > 20 - 6 > 14

Given that each customer buys 2 items.

Let c be the number of customers.

So, number of items bought be the customers = Number of items bought by each customer multiplied by the number of customers = 2c

And as per the question statement,

Number of more items to be sold > 14 (as calculated in above step)

2c>14\\\Rightarrow \bold{c>7}

Therefore, the answer is: <em>More than 7 additional customers are required</em>.

3 0
3 years ago
X= 7 4. Find the equation of a line passing through (5, -6) perpendicular (b) 3x + 5y = (d) 7x - 12y (f) x = 7 (a) 2x + y = 12 (
goldfiish [28.3K]

Given data:

The first set of equations are x+y=4, and x=6.

The second set of equations are 3x-y=12 and y=-6.

The point of intersection of first set of te equations is,

6+y=4

y=-2

The first point is (6, -2).

The point of intersection of second set of te equations is,

3x-(-6)=12

3x+6=12

3x=6

x=2

The second point is (2, -6).

The equation of the line passing through (6, -2) and (2, -6) is,

\begin{gathered} y-(-2)=\frac{-6-(-2)}{2-6}(x-6) \\ y+2=\frac{-6+2}{-4}(x-6) \\ y+2=x-6 \\ y=x-8 \end{gathered}

Thus, the required equation of the line is y=x-8.

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Solve for y like the top equation:
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Arturiano [62]

Answer:

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