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Sedbober [7]
3 years ago
6

Find the probability that a point choseb at randon the figure will lie in the shaded region. Write your anser as a percentage ro

unding to the nearest hundreth in percentage form

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0
<h3>Answer:  21.46%</h3>

=======================================================

Explanation:

Let's find the area of one of the circles

A = pi*r^2

A = pi*10^2

A = 100pi

One circle is exactly 100pi square meters in area.

Four of the circles then combine to a total area of 4*100pi = 400pi square meters.

The distance along the bottom of the square is equal to two diameters, each diameter being 2r = 2*10 = 20 meters. So the distance along the bottom of the square is 2*20 = 40 meters. The square has an area of 40^2 = 1600 square meters.

The shaded region would therefore have an exact area of 1600-400pi square meters.

This approximates to 1600-400pi = 343.362938564082

Divide this over the area of the square to get the probability we want to find:

343.362938564082/1600 = 0.21460183660256

That's roughly 0.2146, which converts to 21.46%

Mashcka [7]3 years ago
3 0

Answer:

21.5%

Step-by-step explanation:

Find the area of the square, which is 40² or 1600 sq m

Find the area of one circle, multiply it by 4, then subtract that from 1600

A = 100(3.14) = 314

314 x 4 = 1256

1600 - 1256 = 344

Probability of landing in the shaded region is 344/1600 = 21.5%

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If f(1)=3 and f(n)=-2f(n-1)+1,then f(5)=
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F(5) = - 2f(4) + 1
f(4) = -2f(3) + 1
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A boat that is out in sea is 400m from the bottom of a cliff. A lighthouse is at the top of the cliff. The lighthouse is 52m tal
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3 years ago
Suppose that scores on a test are normally distributed with a mean of 80 and a standard deviation of 8. Which of the following q
Ilia_Sergeevich [38]

Answer:

a) 86.73

b) 90.24

c) 10.56% scoring more than 90

d) 75.8

e) 50% probability that a randomly selected student will score more than 80.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 8

a. Find the 80th percentile.

This is the value of X when Z has a pvalue of 0.8. So X when Z = 0.841.

Z = \frac{X - \mu}{\sigma}

0.841 = \frac{X - 80}{8}

X - 80 = 8*0.841

X = 86.73

b. Find the cutoff for the A grade if the top 10% get an A.

This is the value of X when Z has a pvalue of 0.9. So X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 80}{8}

X - 80 = 8*1.28

X = 90.24

c. Find the percentage scoring more than 90.

This is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{8}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944.

1 - 0.8944 = 0.1056

10.56% scoring more than 90

d. Find the score that separates the bottom 30% from the top 70%.

This is the value of X when Z has a pvalue of 0.3. So X when Z = -0.525.

Z = \frac{X - \mu}{\sigma}

-0.525 = \frac{X - 80}{8}

X - 80 = 8*(-0.525)

X = 75.8

e. Find the probability that a randomly selected student will score more than 80.

This is 1 subtracted by the pvalue of Z when X = 80.

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 80}{8}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5

50% probability that a randomly selected student will score more than 80.

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Answer:

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Step-by-step explanation:

b = (-1+3)/2 = 1

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|x - 1| ≤ 2

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