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Sedbober [7]
3 years ago
6

Find the probability that a point choseb at randon the figure will lie in the shaded region. Write your anser as a percentage ro

unding to the nearest hundreth in percentage form

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0
<h3>Answer:  21.46%</h3>

=======================================================

Explanation:

Let's find the area of one of the circles

A = pi*r^2

A = pi*10^2

A = 100pi

One circle is exactly 100pi square meters in area.

Four of the circles then combine to a total area of 4*100pi = 400pi square meters.

The distance along the bottom of the square is equal to two diameters, each diameter being 2r = 2*10 = 20 meters. So the distance along the bottom of the square is 2*20 = 40 meters. The square has an area of 40^2 = 1600 square meters.

The shaded region would therefore have an exact area of 1600-400pi square meters.

This approximates to 1600-400pi = 343.362938564082

Divide this over the area of the square to get the probability we want to find:

343.362938564082/1600 = 0.21460183660256

That's roughly 0.2146, which converts to 21.46%

Mashcka [7]3 years ago
3 0

Answer:

21.5%

Step-by-step explanation:

Find the area of the square, which is 40² or 1600 sq m

Find the area of one circle, multiply it by 4, then subtract that from 1600

A = 100(3.14) = 314

314 x 4 = 1256

1600 - 1256 = 344

Probability of landing in the shaded region is 344/1600 = 21.5%

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X-25/14=6/7 find the solution
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x= \frac{6}{7} + \frac{25}{14} = \frac{12+25}{14} = \frac{37}{14}
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3 years ago
<img src="https://tex.z-dn.net/?f=6%5Csqrt%7B3%7D%2B2%281-%5Csqrt%7B27%7D%29%3D2" id="TexFormula1" title="6\sqrt{3}+2(1-\sqrt{27
skelet666 [1.2K]

Answer:

This is true.

Step-by-step explanation:

Step 1: see that √27 is the same as √3*3*3 and thus 3√3

Step 2: remove parenthesis so that 2(1-3√3) becomes 2 - 6√3

Step 3: observe that the equation now becomes 6√3 + 2 - 6√3 = 2

if you simplify any further, you are left with 0=0, which is true.

Comment if there is any step that requires more details...

3 0
3 years ago
Read 2 more answers
A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
2 years ago
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