What is the answer?ppphsusudhdhd

Mathematics

1 answer:

nevsk [136]4 years ago

6 0

6x+3+5x+1=180
x=16
(5*16)+1=81
1=81

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Pls help pls show working brainliest given to clearest answer

myrzilka [38]

Answer:

$x_1=\frac{1+\sqrt{61}}{6}\approx1.47,x_2=\frac{1-\sqrt{61}}{6}\approx-1.14$

Step-by-step explanation:

To solve a non-factorable quadratic equation in the form of $ax^2+bx+c=0$ , you need to use the quadratic formula where $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ :

$3x^2+x-5=0$

$x=\frac{-1\pm\sqrt{1^2-4(3)(-5)}}{2(3)}$

$x=\frac{-1\pm\sqrt{1+60}}{6}$

$x=\frac{-1\pm\sqrt{61}}{6}$

Because of the $\pm$ sign, quadratic equations always have two solutions, whether both are real, only one is real, or both are complex (in the form of $a+bi$ where $a$ is the real part and $b$ is the imaginary part where $i=\sqrt{-1}$ ). In this case, because the discriminant is positive (defined as $b^2-4ac$ ), then there are 2 real solutions.