There are two choices for each child: overweight (o) or underweight (u). So if the first child is o the next can be o or u. If the first is u the second can be o or u. This gives four possibilities. Here the first child is the letter noted first and the second is the one listed second:
OO
OU
UO
UU
There are 4 outcomes and if each is equally likely then the probability of each is 1/4. Thus the probability of UU is 1/4
The probability of one underweight and one over weight is 1/2 because in two of the outcomes listed above there is one O and one U (namely OU and UO). Since there are 4 outcomes the probability is 2/4 = 1/2
Blackmail them. Kidding ask the teacher for a new partner or just do it on your own and tell the teacher to give you all the points then,
Answer:
(a + 2b)(a - b)
Step-by-step explanation:
Assuming you require the expression to be factored
Given
a² + ab - b² ← factor out from each term
= (a² + ab - 2b²) ← factor the quadratic
Consider the factors of the coefficient of the b² term(- 2) which sum to give the coefficient of the ab- term (+ 1)
The factors are + 2 and - 1, since
2 × - 1 = - 2 and 2 - 1 = + 1, thus
a² + ab - 2b² = (a + 2b)(a - b) and
a² + ab - b² = (a + 2b)(a - b)
I believe the correct answer is 0
Step-by-step explanation:
To solve this question, we use an abbreviation formula called BODMAS which is:
B = Brackets
O = Of
D = Division
M = Multiplication
A = Addition
S = Subtraction
We solve each element that is available in the order of the abbreviated letter.
1. We solve the brackets:
2. We solve the second bracket:
The equation now is 
3. We now solve addition first:
4. Now we solve the subtraction:
The answer then = 0
Answer:
ΔEFG is an isosceles triangle
Step-by-step explanation:
