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Inessa [10]
3 years ago
12

55% of the attending crowd was female. If the crowd has 1345 people, how many females are there ?

Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0
Not sure but maybe 740
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You can spend 3.57 per square foot of carpet. You take 14*14 and then you take that number and divide 700 by it
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Quick!! I need help with this question!
d1i1m1o1n [39]

1. 60 / 1/8 * 3/4

2. 3/4 * 15

3. 7/8 / 3/4

3 0
3 years ago
Ashton needs $120 but has only saved 60% so far. How much more money does he need
Kamila [148]

Hello there! Ashton needs 48 more dollars.

Well, to start, you want to find 60% of 120. To do this, you first have to convert 60% into a decimal by dividing it by 100.

60/100 = 0.6

Next, multiply 0.6 by your total needed, 120, to finish finding 60% of 120.

120 x 0.6 = 72.

So he already has 72 dollars, but how many more does he need? You can find this by subtracting 72 from 120.

120 - 72 = 48.

So, this means he needs 48 more dollars. I hope this helps and have a great rest of your day! Please let me know if you need further help with this question. :)

3 0
3 years ago
When Carson runs the 400 meter dash, his finishing times are normally distributed with a mean of 63 seconds and a standard devia
Gnom [1K]

Answer: in 95% of races, his finishing time will be between 62 and 64 seconds.

Step-by-step explanation:

The empirical rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean . The empirical rule is further illustrated below

68% of data falls within the first standard deviation from the mean.

95% fall within two standard deviations.

99.7% fall within three standard deviations.

From the information given, the mean is 63 seconds and the standard deviation is 5 seconds.

2 standard deviations = 2 × 0.5 = 1

63 - 1 = 62 seconds

63 + 1 = 64 seconds

Therefore, in 95% of races, his finishing time will be between 62 and 64 seconds.

6 0
3 years ago
A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=5 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

6 0
3 years ago
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