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Vlad [161]
2 years ago
15

The distance between 2 trees is 11 meters. The first tree is 12 meters and the second tree is 29 meters. What is the distance be

tween the tops of the trees?​
Mathematics
2 answers:
AfilCa [17]2 years ago
8 0

Answer:

In ΔABC

AB  

2

=AC  

2

+BC  

2

 

⇒BC  

2

=x  

2

=17  

2

−8  

2

 ⇒x=15m.

Step-by-step explanation:

prisoha [69]2 years ago
7 0

Form a right triangle, with the base being the distance between the trees, 11 meters.

The height would be the difference between the height of the two trees: 29-12 = 17 meters

Now using the Pythagorean theorem calculate the hypotenuse, which would be the distance between the tops:

X ^2 = 11^2 + 17^2

X^2 = 121+ 289

X^2 = 410

X = sqrt(410)

X = 20.24845

The distance is:

Exact answer = sqrt(410) meters

Decimal answer = 20.24845 meters (round the answer as needed)

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GalinKa [24]

Problem 5

d = 29 = diameter

r = d/2 = 29/2 = 14.5 = radius

SA = surface area of sphere

SA = 4*pi*r^2

SA = 4*pi*(14.5)^2

SA = 841pi

SA = 841*3.14

SA = 2,640.74 square inches

To convert from square inches to square feet, we divide by 144. This is because 12^2 = 144.

2,640.74 square inches = (2,640.74)/144 = 18.3 sq ft

<h3>Answer: 18.3 square feet (approximate)</h3>

=====================================

Problem 6

d = 10.7 = diameter

r = d/2 = 10.7/2 = 5.35 = radius

L = 22.3 = slant height

SA = surface area of the cone

SA = pi*r^2 + pi*r*L

SA = pi*(5.35)^2 + pi*5.35*22.3

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Algebraic Reasoning please help!
stiv31 [10]

Answer:

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Step-by-step explanation:

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and

\left[\begin{array}{ccc}0&6&2\end{array}\right] * \left[\begin{array}{ccc}2\\0\\1\end{array}\right] = (0 * 2) + (6 * 0) + (2 * 1) = 0 + 0 + 2= 2

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