Let's see which of these best measures the data.
The mean is the average, or the sum of all numbers divided by the total numbers there are.
4.8 + 3 + 2.7 + 4.4 + 4.8 + 9.9 = 29.6
There are 6 numbers total.
29.6/6 = 4.93.
The mean is 4.93.
Let's try our median. The median is the middle number of a sequence listed from least to greatest. I will make the list for you.
2.7, 3, 4.4, 4.8, 4.8, 9.9.
Cross out the smallest number with the greatest number.
3, 4.4, 4.8, 4.8.
4.4, 4.8.
Since we do not have a middle number, we must see what number is in the middle of 4.4, and 4.8. To determine this, we must average. Add 4.4 and 4.8, then divide by 2.
9.2/2 = 4.6.
4.6 is our median.
The mode is the number that appears the most, so let's find the number that is the most frequent.
4.8 is our mode.
The best number that will fit in this to make it work out is 4.6.
The median is your answer, B.)
I hope this helps!
Answer:
20, 4
Step-by-step explanation:
Let's assume total number of students registered is n
Last week n/4 people are absent
so people present are n - n/4 = <u>3n/4</u>
Today after return of Jen 1/5 n are absent
so people present are n - n/5 = 4n/5
which is also equal to last week present people + 1 (Jen)
= 3n/4 + 1
= (3n + 4) / 4
so (3n + 4) / 4 = 4n/5
=> 3n + 4 = 4n/5 * 4
=> (3n + 4) * 5 = 16n
=> 15n + 20 = 16n
=> 20 = n
=> n = 20
So total students registered for class is 20
today no of people absent = n/5 = 20/5 = 4
In this case, since one equation is in the form of x=, substitution would be best for this problem. Simply plug in 4y + 8 in place of x in the second equation, solve for y, then plug that value into the first equation to find x.
Answer:
There is sufficient evidence at the 0.05 level
Null hypothesis ; H0 : p = 0.47
Alternative hypothesis : H1 : p ≠ 0.47
Step-by-step explanation:
percentage favoring construction of adjoining community = 47%
level = 0.05
To determine if the 0.05 confidence level is enough to support the major's claim we have to state the Null and alternative hypothesis
Null hypothesis ; H0 : p = 0.47
Alternative hypothesis : H1 : p ≠ 0.47
Um, I don't know if I actually answered the question, but I think that the second one is cheaper to rent.
