the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Vertex form: y = a(x - h)² + k
h = 2
k = -1
y = 0
x = 5
0 = a(5 - 2)² - 1
0 = 9a - 1
a = 1/9
Answer:
8:16
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
You forgot to give the coordinates of C.
Note that, the mapping for 90° clockwise rotation around the origin is given by:
Assuming the coordinates of C were (-6,6), then the coordinates of C after a 90° clockwise rotation
around the origin is (-6,-6)
