u3uwi2i2i3ij3j3ui
Step-by-step explanation:
ii3jj3i3i3i3i3i3ii3u3ieu so
Answer:
Step-by-step explanation:
We have to take the derivatives for both functions and replace in the differential equation. Hence
for y=e^{-5x}:
for y=e^{6x}:
Now we replace in the differential equation y'' − y' − 30y = 0
for y=e^{-5x}:
for y=e^{6x}:
Now, to know if both function are linearly independent we calculate the Wronskian
I hope this is useful for you
Best regard
Answer:
3
Step-by-step explanation:
Set the denominator in
3
x
2
−
2
x
−
15
equal to
0
to find where the expression is undefined.
x
2
−
2
x
−
15
=
0
Solve for
x
.
Tap for more steps...
x
=
5
,
−
3
The domain is all values of
x
that make the expression defined.
Interval Notation:
(
−
∞
,
−
3
)
∪
(
−
3
,
5
)
∪
(
5
,
∞
)
Set-Builder Notation:
{
x
|
x
≠
−
3
,
5
}
1.4 as a mixed number would look like this:
or 1 2/5
Hope this helps you
-AaronWiseIsBae