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3 years ago

Use this definition to find l'(a) at the given number a. f(x) = ✓ 3x + 1, a = 8

Mathematics

1 answer:

yanalaym [24]3 years ago

5 0

F(x)= √3x + 1
a=8

8 √3 + 1 <—Exact form

14.85649646 <—In decimal form

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The quotient of x and 3

ddd [48]

The quotient of x and three is 3/x. quotient is a division term and when the dividend is divided by the divisor, the result is a quotient.

8 0

3 years ago

The ratio of boys to girls in math classes is 5 :7. if there are 60 students in all or her classes, how many are boys

daser333 [38]

Total of ratio 5+7=12

60/12 = 5

For boys 5x5 = 25 boys in her class

(For girls 7x5 = 35)

6 0

3 years ago

Find the 137th odd number.

KIM [24]

The first odd number is 1. The next is 2 more than the previous one.

It's an arithmetic sequence.

The general term of an arithmetic sequence:

$a_n=a_1+(n-1)d$

a_n - n-th term

a_1 - first term

d - common difference.

We have

$a_1=1,\ d=2,\ n=137$

Substitute:

$a_{137}=1+(137-1)(2)=1+(136)(2)=1+272=273$

<h3>Answer: 137th odd number is equal 273.</h3>

3 0

3 years ago

Read 2 more answers

Solve the equation for x 6x-18-3x<27-2x

lisabon 2012 [21]

Answer:

x<9

Step-by-step explanation:

3 0

3 years ago

Vector u has its initial point at (-7, 2) and its terminal point at (11, -5). Vector v has a direction opposite that of vector u

salantis [7]

$\bf u\implies 
\begin{cases}
(-7,2)\\
(11,5)
\end{cases}\implies [11-(-7)]~,~[5-2]\implies (11+7)~,~(5-2)
\\\\\\
\stackrel{\textit{component form}}{\ \textless \ 18~,~3\ \textgreater \ }\\\\
-------------------------------\\\\
||u||=\sqrt{18^2+3^2}\implies ||u||=\sqrt{333}\implies ||u||=\sqrt{9\cdot 37}
\\\\\\
||u||=\sqrt{3^2\cdot 37}\implies ||u||=3\sqrt{37}\\\\
-------------------------------$

$\bf \ \textless \ -18~,~-3\ \textgreater \ \impliedby \textit{opposite vector to \underline{u}}
\\\\\\
3\cdot 3\sqrt{37}\implies 9\sqrt{37}\impliedby \textit{3 times the magnitude of \underline{u}}
\\\\\\
3\ \textless \ -18,-3\ \textgreater \ \implies \stackrel{\textit{component form of "v"}}{\ \textless \ -54~,~-9\ \textgreater \ }\impliedby \textit{3 times as long as \underline{u}}$

7 0

3 years ago

Read 2 more answers