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tatyana61 [14]
3 years ago
6

Question 3 What is the slope of a line that passes through the points (-5,2) & (11, -16)

Mathematics
2 answers:
aev [14]3 years ago
6 0

Answer:m=-9/8

Step-by-step explanation:

irinina [24]3 years ago
4 0
Slope = (y2-y1)/(x2-x1) = (-16-2)/(11- -5) = -18/16 = -9/8
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Elena's account balance with her parents is -5.50$ she adds a certain amount of money to her balance by mowing
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big dawg

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Solve the following equation simultaneously 1/x-5/y=7, 2/x+1/y=3​
maria [59]

Answer:

  (x, y) = (1/2, -1)

Step-by-step explanation:

Subtracting twice the first equation from the second gives ...

  (2/x +1/y) -2(1/x -5/y) = (3) -2(7)

  11/y = -11 . . . . simplify

  y = -1 . . . . . . . multiply by y/-11

Using the second equation, we can find x:

  2/x +1/-1 = 3

  2/x = 4 . . . . . . . add 1

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The solution is (x, y) = (1/2, -1).

_____

<em>Additional comment</em>

If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.

A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).

6 0
2 years ago
A line passes through the points (8, – 7) and (6, – 3). What is its equation in slope-intercept form?
mario62 [17]

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y = − 2 x + 9

Step-by-step explanation:

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4 0
3 years ago
Write the given trinomial if possible as a square of a binomial or as an expression opposite to a square of a binomial: 15ab-9a^
MrMuchimi

Answer:

- \bigg(3a -  \frac{5}{2} b) \bigg)^{2}

Step-by-step explanation:

15ab-9a^2-6  \frac{1}{4} b^2 \\  \\  = 15ab-(3a)^2-\frac{6 \times 4 + 1}{4} b^2 \\  \\ = 15ab-(3a)^2-\frac{24+ 1}{4} b^2 \\  \\ = 15ab-(3a)^2-\frac{25}{4} b^2 \\  \\   = 15ab- (3a)^2- \bigg(\frac{5}{2} b \bigg)^2  \\  \\ =  -  \{ - 15ab + (3a)^2 +  \bigg(\frac{5}{2} b \bigg)^2  \} \\  \\ =  -  \{ (3a)^2 +  \bigg(\frac{5}{2} b \bigg)^2 - 15ab  \} \\  \\  =   - \bigg(3a -  \frac{5}{2} b \bigg)^{2}

3 0
3 years ago
Please help me with precalculus??<br>linear and angular speed
Anit [1.1K]
13)

there are 2π radians in 1 revolution, and there are 60 seconds in 1 minute, so keeping that in mind, then,

\bf \cfrac{4\underline{\pi} }{5~\underline{s}}\cdot \cfrac{rev}{2\underline{\pi} }\cdot \cfrac{60~\underline{s}}{min}\implies \cfrac{4\cdot 60~rev}{5\cdot 2~min}\implies \cfrac{240~rev}{10~min}\implies 24\frac{rev}{min}

14)

 \bf \textit{linear velocity}\\\\&#10;v=rw\quad &#10;\begin{cases}&#10;r=radius\\&#10;w=angular~speed\\&#10;----------\\&#10;v=32\frac{m}{sec}\\&#10;w=100\frac{rev}{min}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\textit{let's convert \underline{w} to }\frac{radians}{sec}

\bf \cfrac{100~\underline{rev}}{\underline{min}}\cdot \cfrac{2\pi }{\underline{rev}}\cdot \cfrac{\underline{min}}{60~sec}\implies \cfrac{100\cdot 2\pi }{60~sec}\implies \cfrac{10\pi }{3~sec}\implies \cfrac{10\pi }{3}\frac{radians}{sec}\\\\&#10;-------------------------------\\\\&#10;v=rw\implies \cfrac{v}{w}=r\implies \cfrac{\frac{30~m}{sec}}{\frac{10\pi }{3~sec}}\implies r=\cfrac{30~m}{\underline{sec}}\cdot \cfrac{3~\underline{sec}}{10\pi }&#10;\\\\\\&#10;r=\cfrac{90}{10\pi }m

15)

what is the radians per seconds "w" in revolutions per minute?  just another conversion like in 13)

\bf \cfrac{\underline{\pi} }{3~\underline{sec}}\cdot \cfrac{rev}{2\underline{\pi }}\cdot \cfrac{60~\underline{sec}}{min}\implies \cfrac{60 ~rev}{3\cdot 2 ~min}\implies \cfrac{60 ~rev}{6 ~min}\implies 10\frac{rev}{min}
4 0
4 years ago
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