Using a calculator.. I need help please .
1 answer:
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If we need our line to pass through point C, then we have to use the x and coordinates of point C in our new equation. If that line is to be perpendicular to AB, we also need to find the slope of AB and then take its opposite reciprocal. First things first. Point C lies at (6, 4) so we will use x = 6 and y = 4 in our equation in a bit. The coordinates of A are (-2, 4) and the coordinates of B are (2, -8) so the slope between them is 
which is -3. The opposite reciprocal of -3 is 1/3. That's the slope we will use along with the points from C to write the new equation. We will do this by plugging in x, y, and m (slope) into the slope-intercept form of a line and solve for b. 
and 4 = 2 + b. So b = 2. That's the y-intercept, the point on the y axis where the line goes through when x is 0. Therefore, the point you're looking for is (0, 2).
Answer:
D. 116
Step-by-step explanation:
V = (1/3)π(4)²(6.9)
V = 36.8π
V ≈ 115.55
<em>Note: You will NEVER use slant height to calculate the area, only to calculate the normal height if unknown. In this problem, we did not use it at all so try not to get confused!</em>
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<h2>BRAINLIEST please if this helped!</h2>