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EleoNora [17]
3 years ago
5

Let ABCD and EFGH be two quadrilaterals such that ABCD ~ EFGH. If AB = 15 cm, EF = 18 cm and the perimeter of ABCD is 40 cm, fin

d the perimeter of EFGH.​
Mathematics
1 answer:
Andrews [41]3 years ago
7 0

Step-by-step explanation:

this photo is correct answer of this question.

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Please help, thank you!
shutvik [7]
65 x6 = 390
80 x 3= 240

390+240 = 630
3 0
3 years ago
Read 2 more answers
When factored completely the expression p^4-81 is equivalent to
spayn [35]
   
\displaystyle\\
p^4 - 81 =\\\\
 =p^4-3^4 =\\\\
= \Big(p^2\Big)^2 - \Big(3^2\Big)^2 =\\\\
=\Big(p^2+3^2\Big)\Big(p^2-3^2\Big)=\\\\
=\boxed{\bf \Big(p^2+3^2\Big)\Big(p+3\Big)\Big(p-3\Big)}



7 0
3 years ago
The function, f(x)=70n-400, models the profit of the instructor of a guitar class per month, where n is the number of students e
zimovet [89]

profit=f(x)

so solve for f(x)=1000

1000=70n-400

add 400 to both sides

1400=70n

divide both sides by 70

20=n

20 students need to be enrolled to make a profit of 1000.00

4 0
3 years ago
Juan’s classroom is shaped like a rectangle.the room is 40 feet long and 25 feet’s wide which rectangle could be scale drawing o
Svetach [21]

I think there's an image needed to answer this question?

I tried answering without, but you do need the image.

If the length is 40 and the width is 25, the ration of length:width is 40:25.

This can be simplified to 8:5

So the answer would be any drawing with the following dimensions:

1. length 8 ft and width 5 ft

2. length 16 ft and width 10 ft

3. length 24 ft and width 15 ft

4. length 32 ft and width 20 ft

5. length 40 ft and width 25 ft

It's most likely not the last 3 because the sizes are very big, but yeah a scale drawing maintains the same ratio so I assume one of the options for your answers is gonna be one of the answers from 1 - 4 above (5 is the given dimensions so I highly doubt that's the answer)

8 0
3 years ago
Find the distance between A and B.
Papessa [141]

Answer:

The result is d = 2\sqrt{5} units.

Step-by-step explanation:

The coordinates for A and B:

A = (-2, 0)

B = (2, 2)

-To find the distance between A and B, you need the distance formula:

d = \sqrt{(x_{2} - x_{1})^2 + (y_{2}-y_{1})^2} Where the first coordinate is (x_{1},y_{1}) and  the second coordinate is (x_{2}, y_{2}).

-Use the coordinates A and B for the equation:

d = \sqrt{(2+2)^2 + (2-0)^2}

-Then, you solve the equation:

d = \sqrt{(2+2)^2 + (2-0)^2}

d = \sqrt{(4)^2 + (2)^2}

d = \sqrt{16 + 4}

d = \sqrt{20}

d = 2\sqrt{5}

So, therefore the distance is 2\sqrt{5} units.

7 0
4 years ago
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