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3 years ago

At what point in the order of operations should you simplify exponents in an expression?

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

Second step
PEMDAS
Parenthesis exponents division addition subtraction

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heba ate 1/12 of a box of cereal now the box is 3/4 full what fraction of a full box was there before heba ate it

abruzzese [7]

Now box is 3/4 full

3/4 = 3/4*1

3/4 = 3/4 * 3/3 = 9/12

Box is 9/12 full after heba ate 1/12 of a box of cereal

Initial fraction will be 9/12+1/12

=10/12= 5/6

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3 years ago

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3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

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3 years ago

At Libby’s art and crafts, spoils of thread and 5 yards of fabric cost $22.33.

vazorg [7]

How are you supposed to solve this???

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